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digitalmars.D.learn - Re: How are 2D static arrays allocated?

Jarrett Billingsley Wrote:

 You.. can't actually allocate a static array on the heap using new.
 At least not directly.  It's kind of an embarrassing hole in the
 syntax.  In fact, I'm not sure if you can even get a static array to
 point onto the heap, since a static array "reference" is treated like
 a value type when assigned to, so if you do something like:
 int[3][4] b = (new int[3][4][](1))[0];
 The weirdness on the right-hand-side is needed to get around the
 compiler "helpfully" rewriting "new int[3][4]" as "new int[][](3, 4)".
  But this code will simply allocate a static array on the heap, and
 then copy its contents onto the stack.  Dumb.

writeln(typeof(rg2).stringof); //int[10u][] writeln(cast(size_t)&rg2[1]-cast(size_t)&rg2[0]); //40 As you can see it allocates contunous int[10][20] and assigns it to dynamic array int[10][]. Which is nearly what topicstarter wants. Well, border checks will be dynamic for the first index.
Nov 07 2008