• Jesse Phillips <jessekphillips+D gmail.com> Aug 01 2011
• David Nadlinger <see klickverbot.at> Aug 01 2011
• Jesse Phillips <jessekphillips+d gmail.com> Aug 01 2011
• David Nadlinger <see klickverbot.at> Aug 02 2011

Jesse Phillips <jessekphillips+D gmail.com> writes:

Andrej Mitrovic Wrote:

 I'm currently using this:
 
 import std.algorithm;
 import std.array;
 import std.random;
 import std.range;
 
 void main()
 {
     auto arr2 = array(map!( (int){ return uniform(0, 1024); })(iota(0, 1024)));
 }
 
 Is there a simpler way to do get an array of random values?


Untested:

auto arr = new int[1024];
fill(arr, uniform(0, 1024));

David Nadlinger <see klickverbot.at> writes:

On 8/2/11 3:40 AM, Jesse Phillips wrote:
 Andrej Mitrovic Wrote:
 Is there a simpler way to do get an array of random values?


 Untested:

 auto arr = new int[1024];
 fill(arr, uniform(0, 1024));


This does a great job of creating an array containing the same random 
value 1024 times. ;)

David

Jesse Phillips <jessekphillips+d gmail.com> writes:

On Tue, 02 Aug 2011 03:48:03 +0200, David Nadlinger wrote:

 On 8/2/11 3:40 AM, Jesse Phillips wrote:
 Andrej Mitrovic Wrote:
 Is there a simpler way to do get an array of random values?


 Untested:

 auto arr = new int[1024];
 fill(arr, uniform(0, 1024));


 This does a great job of creating an array containing the same random
 value 1024 times. ;)
 
 David


Fine, let me provide a tested one:

import std.algorithm;
import std.array;
import std.random;
import std.range;

void main()
{
    auto arr = new int[1024];
    fill(arr, randomCover(iota(0,1024), rndGen));
}


Knew I had done something with fill before.

David Nadlinger <see klickverbot.at> writes:

On 8/2/11 6:42 AM, Jesse Phillips wrote:
      auto arr = new int[1024];
      fill(arr, randomCover(iota(0,1024), rndGen));


Note that this produces a random permutation of the numbers 0 to 1023, 
which may or may not be what you want.

David