• Marcone (6/6) Dec 05 2019 Simple example:
• Andrea Fontana (8/14) Dec 05 2019 One solution:
• Bastiaan Veelo (22/28) Dec 05 2019 .splitLines[0] already just produces "Hi", containing no "\", so

Marcone <marcone email.com> writes:

Simple example:

writeln("Hi\nHow are 
you?\nGood".splitLines()[0][0..?lastIndexOf(r"\")]);

How to refer to this string in lastIndexOf() without create a 
variable?

Thank you.

Andrea Fontana <nospam example.com> writes:

On Thursday, 5 December 2019 at 11:28:51 UTC, Marcone wrote:
 Simple example:

 writeln("Hi\nHow are 
 you?\nGood".splitLines()[0][0..?lastIndexOf(r"\")]);

 How to refer to this string in lastIndexOf() without create a 
 variable?

 Thank you.

One solution:

     writeln(
         "Hello\nHow are you?\nGood"
         .splitLines()
         .map!(x => x[0..x.lastIndexOf("o")])
     );

But be careful: lastIndexOf could be < 0 if string is not found.

Bastiaan Veelo <Bastiaan Veelo.net> writes:

On Thursday, 5 December 2019 at 11:28:51 UTC, Marcone wrote:
 Simple example:

 writeln("Hi\nHow are 
 you?\nGood".splitLines()[0][0..?lastIndexOf(r"\")]);

 How to refer to this string in lastIndexOf() without create a 
 variable?

 Thank you.

.splitLines[0] already just produces "Hi", containing no "\", so 
this example is a bit broken.


#Hi

You could write a function to work around having to declare a 
variable:

   string upto(string input, string delim)
   {
       return input[0 .. input.countUntil(delim)];
   }

   void main()
   {
       writeln(upto("Up to colon: skip this", ":")); // Up to colon
       writeln("Up to colon: skip this".upto(":")); // Up to colon
   }

You can use a function literal or lambda, but it isn't pretty:

   writeln((string s){return s[0..s.countUntil(":")];}("Up to 
colon: skip this")); // Up to colon
   writeln((s => s[0..s.countUntil(":")])("Up to colon: skip 
this")); // Up to colon

Bastiaan.