• orgoton <orgoton mindless.com> May 23 2007
• Deewiant <deewiant.doesnotlike.spam gmail.com> May 23 2007
• "Jarrett Billingsley" <kb3ctd2 yahoo.com> May 23 2007

orgoton <orgoton mindless.com> writes:

The program

import std.stdio;
import std.string;

void main ()
{
writefln("Sizeof(void)="~toString(void.sizeof));
}

compiles and outputs "sizeof(void)=1". Is this supposed to happen? I mean, in
C, it is an error to request sizeof(void) (compiler fails).

Deewiant <deewiant.doesnotlike.spam gmail.com> writes:

orgoton wrote:
 The program
 
 import std.stdio;
 import std.string;
 
 void main ()
 {
 writefln("Sizeof(void)="~toString(void.sizeof));
 }
 
 compiles and outputs "sizeof(void)=1". Is this supposed to happen? I mean, in
C, it is an error to request sizeof(void) (compiler fails).


Yes, it is supposed to happen. I can't find a Walter quote or documentation for
it, but IIRC void.sizeof is defined as 1 in order for void arrays to work
properly.

-- 
Remove ".doesnotlike.spam" from the mail address.

"Jarrett Billingsley" <kb3ctd2 yahoo.com> writes:

"Deewiant" <deewiant.doesnotlike.spam gmail.com> wrote in message 
news:f31fg3$57$1 digitalmars.com...
 Yes, it is supposed to happen. I can't find a Walter quote or 
 documentation for
 it, but IIRC void.sizeof is defined as 1 in order for void arrays to work 
 properly.


I want to say it's defined as the smallest addressable type on the system. 
Like you said, I don't remember where that was mentioned.