• pascal111 (6/6) Jul 25 2022 I tried to type small program, and tried to use "string" data
• Adam D Ruppe (4/7) Jul 25 2022 the overload you used modifies the array you give it
• rikki cattermole (16/16) Jul 25 2022 The version of readln you are using is[0]. This works by taking in a

pascal111 <judas.the.messiah.111 gmail.com> writes:

I tried to type small program, and tried to use "string" data 
type with "readln", but the compiler refused it, and I had to use 
"char[]". So, if we can't use "string" with "readln", so what's 
its benefit? why we need to use it?

Code source:
https://github.com/pascal111-fra/D/blob/main/proj01.d

Adam D Ruppe <destructionator gmail.com> writes:

On Monday, 25 July 2022 at 19:55:40 UTC, pascal111 wrote:
 I tried to type small program, and tried to use "string" data 
 type with "readln", but the compiler refused it, and I had to 
 use "char[]".

the overload you used modifies the array you give it

try

string s = readln();

rikki cattermole <rikki cattermole.co.nz> writes:

The version of readln you are using is[0]. This works by taking in a 
buffer of memory to write out, and returns how many codepoints were stored.

Because you are not reusing memory, not using this form you can of 
course use string[1] instead, rather than ``char[]``.

```d
string s = readln();
```

The definition of string is[2]:

```d
alias string  = immutable(char)[];
```

Note the immutable there, which means that each value in the slice 
cannot be modified. Hence why it can't be used as a buffer.

[0] https://dlang.org/phobos/std_stdio.html#.readln.2
[1] https://dlang.org/phobos/std_stdio.html#.readln
[2] https://github.com/dlang/dmd/blob/master/druntime/src/object.d#L69