digitalmars.D.learn - std.datetime for month integer
- dsmith (7/7) Jul 18 2011 Recall that std.date used the following to retrieve a month in integer f...
- Jonathan M Davis (8/20) Jul 18 2011 Cast it to an integer (or use std.conv.to will probably work - it _shoul...
- dsmith (12/20) Jul 18 2011 Thank you, it works as planned, now as:
Recall that std.date used the following to retrieve a month in integer form (0
.. 11):
auto Now = std.date.getUTCtime();
writeln(std.date.monthFromTime(Now));
Using std.datetime, the following yields the abbreviated month name:
auto Now = Clock.currTime();
writefln("%s", Now.month); // --> jul
Now, how can std.datetime be used to print the month in integer form?
Jul 18 2011
On Monday 18 July 2011 16:01:06 dsmith wrote:
Recall that std.date used the following to retrieve a month in integer form
(0 .. 11):
auto Now = std.date.getUTCtime();
writeln(std.date.monthFromTime(Now));
Using std.datetime, the following yields the abbreviated month name:
auto Now = Clock.currTime();
writefln("%s", Now.month); // --> jul
Now, how can std.datetime be used to print the month in integer form?
Cast it to an integer (or use std.conv.to will probably work - it _should_ at
least; if it doesn't, it needs to be fixed). std.datetime.Month is a named
enum. So, presumably that's why you're seeing it as a the enum's name. I think
that that's only happening because you're using it directly in writefln though.
If you assigned it to a variable first, I think that it would just be a ubyte,
since that's the type of the Month enum).
- Jonathan M Davis
Jul 18 2011
Thank you, it works as planned, now as: int mo = Now.month; // --> 7 == Repost the article of Jonathan M Davis (jmdavisProg gmx.com) == Posted at 2011/07/18 12:14 to digitalmars.D.learn









Jonathan M Davis <jmdavisProg gmx.com> 