• Vino (35/35) Nov 10 2020 Hi All,
• sarn (22/27) Nov 10 2020 This is iterating over all the elements in data2 and outputting
• Vino (3/8) Nov 10 2020 Hi Sarn,

Vino <akashvino79 gmail.com> writes:

Hi All,

    Request your help, the below code output's as below hence 
request your help on hot to get the output as below(Required 
Output).

Output
DEV Cluster
QAS Cluster

Required Output

DEV Cluster
DEV Cluster
DEV Cluster
QAS Cluster

Code
import std.container.array;
import std.stdio: writeln;
import std.algorithm: canFind;
import std.typecons: Tuple, tuple;

void main () {
Array!string data1;
Array!(Tuple!(string,string)) data2;
Array!string rs;

data1.insertBack("DEV Systems");
data1.insertBack("DEV Systems");
data1.insertBack("DEV Systems");
data1.insertBack("QAS Systems");

data2.insertBack(tuple("DEV Systems","DEV Cluster"));
data2.insertBack(tuple("QAS Systems","QAS Cluster"));

foreach(i; data2[]) {
    if(data1[].canFind(i[0])) {
      writeln(i[1]);
   }
}
}

From,
Vino.B

sarn <sarn theartofmachinery.com> writes:

On Tuesday, 10 November 2020 at 08:19:15 UTC, Vino wrote:
 foreach(i; data2[]) {
    if(data1[].canFind(i[0])) {
      writeln(i[1]);
   }
 }

This is iterating over all the elements in data2 and outputting 
some of them, so the output will never be longer than data2.

It looks like you want to iterate over data1.  Something like 
this:

foreach(i; data1[]) {
   auto result = data2[].find!((p, x) => p[0] == x)(i);
   if (!result.empty) writeln(result.front[1]);
}

However, you could also use an associative array for data2:

string[string] data2 = [
   "DEV Systems": "DEV Cluster",
   "QAS Systems": "QAS Cluster",
];

foreach (i; data1[]) {
   if (auto v = i in data2) writeln(*v);
}

The "in" operator returns a pointer to the value in data2 at 
index "i", or else a null pointer.

See more info here:
https://ddili.org/ders/d.en/aa.html
https://dlang.org/spec/hash-map.html

Vino <akashvino79 gmail.com> writes:

On Tuesday, 10 November 2020 at 09:47:06 UTC, sarn wrote:
 On Tuesday, 10 November 2020 at 08:19:15 UTC, Vino wrote:
 [...]

 This is iterating over all the elements in data2 and outputting 
 some of them, so the output will never be longer than data2.

 [...]

Hi Sarn,

   Thank you very much