• Orion (14/14) Apr 27 In which programming scenarios should alias be used instead of
• user1234 (15/30) Apr 28 Alias is the proper way, there's specifications for them to work
• monkyyy (3/18) Apr 28 aliases for types, overload sets
• user1234 (3/5) Apr 28 According to me that's a very bad advice. I'm more on "never
• monkyyy (4/11) Apr 28 enum N=1024;
• user1234 (3/15) Apr 28 this is totally unrelated to the topic. i.e function as

Orion <vlad000ff yopmail.com> writes:

In which programming scenarios should alias be used instead of 
enum?

So far I have only found a simplified notation of a generic 
lambda:
alias id = (x) => x; x; , which does not work in the case of enum.

There is also a difference in overloading a non-generic lambda:

alias m = (int x) => x;
alias m = (float x) => 0.5 + x;
- alias overloads a function with the same name.

enum e = (int x) => x;
///enum e = (float x) => x; //error
- enum does not.

At the compiler level, enum lambda is represented as a literal.
But how is alias represented? As an expression?

user1234 <user1234 12.de> writes:

On Monday, 28 April 2025 at 04:59:24 UTC, Orion wrote:
 In which programming scenarios should alias be used instead of 
 enum?

 So far I have only found a simplified notation of a generic 
 lambda:
 alias id = (x) => x; x; , which does not work in the case of 
 enum.

 There is also a difference in overloading a non-generic lambda:

 alias m = (int x) => x;
 alias m = (float x) => 0.5 + x;
 - alias overloads a function with the same name.

 enum e = (int x) => x;
 ///enum e = (float x) => x; //error
 - enum does not.

 At the compiler level, enum lambda is represented as a literal.
 But how is alias represented? As an expression?

Alias is the proper way, there's specifications for them to work 
as a way to overload whereas with enum there's no support. 
Rememeber that

```
enum e = (int x) => x;
```

is a shortcut to

```
enum e
{
     e = (int x) => x
}
```

so always use `alias`.

monkyyy <crazymonkyyy gmail.com> writes:

On Monday, 28 April 2025 at 04:59:24 UTC, Orion wrote:
 In which programming scenarios should alias be used instead of 
 enum?

 So far I have only found a simplified notation of a generic 
 lambda:
 alias id = (x) => x; x; , which does not work in the case of 
 enum.

 There is also a difference in overloading a non-generic lambda:

 alias m = (int x) => x;
 alias m = (float x) => 0.5 + x;
 - alias overloads a function with the same name.

 enum e = (int x) => x;
 ///enum e = (float x) => x; //error
 - enum does not.

 At the compiler level, enum lambda is represented as a literal.
 But how is alias represented? As an expression?

aliases for types, overload sets

enum for litterals

user1234 <user1234 12.de> writes:

On Monday, 28 April 2025 at 20:05:34 UTC, monkyyy wrote:
 aliases for types, overload sets

 enum for litterals

According to me that's a very bad advice. I'm more on "never 
enum". Do you have any example where enum is better ?

monkyyy <crazymonkyyy gmail.com> writes:

On Monday, 28 April 2025 at 22:16:47 UTC, user1234 wrote:
 On Monday, 28 April 2025 at 20:05:34 UTC, monkyyy wrote:
 aliases for types, overload sets

 enum for litterals

 According to me that's a very bad advice. I'm more on "never 
 enum". Do you have any example where enum is better ?

enum N=1024;

int[N] array1;
int[N] array2;

user1234 <user1234 12.de> writes:

On Monday, 28 April 2025 at 22:47:35 UTC, monkyyy wrote:
 On Monday, 28 April 2025 at 22:16:47 UTC, user1234 wrote:
 On Monday, 28 April 2025 at 20:05:34 UTC, monkyyy wrote:
 aliases for types, overload sets

 enum for litterals

 According to me that's a very bad advice. I'm more on "never 
 enum". Do you have any example where enum is better ?

 enum N=1024;

 int[N] array1;
 int[N] array2;

this is totally unrelated to the topic. i.e function as 
expressions.