digitalmars.D.learn - Why doesn't this work in D2?
- Jacob Carlborg (18/18) Jun 27 2010 Why doesn't the following code work in D2 (it works in D1)?
- Ellery Newcomer (2/10) Jun 27 2010 "asd".foo(cast(immutable) 's');
- Simen kjaeraas (12/28) Jun 27 2010 In D2, strings are of type immutable(char)[], so your T would be
- bearophile (13/16) Jun 27 2010 Yes, this was my solution.
- Jacob Carlborg (6/37) Jun 27 2010 That's annoying, specially since "char" is a value type. I would
- BCS (20/23) Jun 27 2010 One solution would be to have templates strip off const/immutable from t...
- Jacob Carlborg (5/26) Jun 28 2010 I don't think I understand what you're showing here. How would I strip
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Philippe Sigaud
(57/58)
Jun 28 2010
On Mon, Jun 28, 2010 at 10:56, Jacob Carlborg
wrote: - Steven Schveighoffer (15/20) Jun 28 2010 No, that is not true. It's still an array of immutable(char). The
- Philippe Sigaud (9/29) Jun 28 2010 All that I can say is that it instantly broke dozens of unit tests in my
- Jacob Carlborg (16/75) Jun 28 2010 Hmm, now I don't know what I'm doing, I thought you could do something
- BCS (8/19) Jun 28 2010 I was proposing a language change Sorry for any confusion. The idea is t...
- Jacob Carlborg (4/21) Jun 28 2010 Ok, now I understand.
Why doesn't the following code work in D2 (it works in D1)? void foo (T) (in T[] a, T b) { } void main () { "asd".foo('s'); } The error I get is: main.d(10): Error: template main.foo(T) does not match any function template declaration main.d(10): Error: template main.foo(T) cannot deduce template function from argument types !()(string,char) It seems to be some problem with the "b" argument, if I change that to "char" it works. -- /Jacob Carlborg
Jun 27 2010
On 06/27/2010 12:18 PM, Jacob Carlborg wrote:Why doesn't the following code work in D2 (it works in D1)? void foo (T) (in T[] a, T b) { } void main () { "asd".foo('s'); }"asd".foo(cast(immutable) 's');
Jun 27 2010
Jacob Carlborg <doob me.com> wrote:Why doesn't the following code work in D2 (it works in D1)? void foo (T) (in T[] a, T b) { } void main () { "asd".foo('s'); } The error I get is: main.d(10): Error: template main.foo(T) does not match any function template declaration main.d(10): Error: template main.foo(T) cannot deduce template function from argument types !()(string,char) It seems to be some problem with the "b" argument, if I change that to "char" it works.In D2, strings are of type immutable(char)[], so your T would be immutable(char). However, 's' is a simple, unadorned char. Ways to fix this would include: void foo(T)(const T[] a, const T b){ ... } void foo(T,U)(const T[] a, U b) if (is(Unqual!T == Unqual!U)) { ... } -- Simen
Jun 27 2010
Simen kjaeraas:void foo(T,U)(const T[] a, U b) if (is(Unqual!T == Unqual!U)) { ... }Yes, this was my solution. My first solution was: import std.traits: Unqual; void foo(T)(T[] a, Unqual!T b) {} void main () { "asd".foo('s'); } But it doesn't work, and I don't know if it's supposed to work. A problem with Unqual is that it strips away too much, so something like this can be better: void foo(TA, T)(const TA[] a, T b) if (is(Deconst!TA == Deconst!T)) {} Bye, bearophile
Jun 27 2010
On 2010-06-27 19:26, Simen kjaeraas wrote:Jacob Carlborg <doob me.com> wrote:That's annoying, specially since "char" is a value type. I would preferably have a solution for both D1 and D2. Can I use a template to cast/alias away the immutable part? -- /Jacob CarlborgWhy doesn't the following code work in D2 (it works in D1)? void foo (T) (in T[] a, T b) { } void main () { "asd".foo('s'); } The error I get is: main.d(10): Error: template main.foo(T) does not match any function template declaration main.d(10): Error: template main.foo(T) cannot deduce template function from argument types !()(string,char) It seems to be some problem with the "b" argument, if I change that to "char" it works.In D2, strings are of type immutable(char)[], so your T would be immutable(char). However, 's' is a simple, unadorned char. Ways to fix this would include: void foo(T)(const T[] a, const T b){ ... } void foo(T,U)(const T[] a, U b) if (is(Unqual!T == Unqual!U)) { ... }
Jun 27 2010
Hello Jacob,That's annoying, specially since "char" is a value type. I would preferably have a solution for both D1 and D2. Can I use a template to cast/alias away the immutable part?One solution would be to have templates strip off const/immutable from the top level of args. void F1(T)(T t) { pragam(msg,typeof(t).stringof); } string s1; immutable(char[]) s2 char[] s3 F1(s1); // immutable(char)[] // all as normal F1(s2); // immutable(char)[] // making a mutable copy of a immutable value is OK F1(s3); // char[] // all as normal void F2(T)(immutable T t) { pragam(msg,typeof(t).stringof); } F2(s1); // immutable(char[]) // making an immutable copy of a mutable reference to immutable data is ok F2(s2); // immutable(char[]) // all as normal F2(s3); // error, invalid conversion This solution would match the proposal that popped up a while ago to allow value assignment from const/immutable to mutable. -- ... <IXOYE><
Jun 27 2010
On 2010-06-28 02:28, BCS wrote:Hello Jacob,I don't think I understand what you're showing here. How would I strip off the const/immutable with a template ? -- /Jacob CarlborgThat's annoying, specially since "char" is a value type. I would preferably have a solution for both D1 and D2. Can I use a template to cast/alias away the immutable part?One solution would be to have templates strip off const/immutable from the top level of args. void F1(T)(T t) { pragam(msg,typeof(t).stringof); } string s1; immutable(char[]) s2 char[] s3 F1(s1); // immutable(char)[] // all as normal F1(s2); // immutable(char)[] // making a mutable copy of a immutable value is OK F1(s3); // char[] // all as normal void F2(T)(immutable T t) { pragam(msg,typeof(t).stringof); } F2(s1); // immutable(char[]) // making an immutable copy of a mutable reference to immutable data is ok F2(s2); // immutable(char[]) // all as normal F2(s3); // error, invalid conversion This solution would match the proposal that popped up a while ago to allow value assignment from const/immutable to mutable.
Jun 28 2010
On Mon, Jun 28, 2010 at 10:56, Jacob Carlborg <doob me.com> wrote: Something to keep in mind: as of 2.04x (.045? maybe), the way UTF-8 / UTF-32 is managed was changed. "asd" is an array of immutable(dchar), not imutable(char). At least DMD tells me that its element type is 'dchar'. So your function can be done this way in D2: void foo(T,U)(in T[] a, U b) if (is(U : Unqual!T)) // that compiles only if b can be cast to A { writeln(a,b); } "asd".foo('s'); // prints "asds". is(U == Unqual!T) does not work, for U is 'char' while Unqual!T is 'dchar'. More generally, using ranges and not arrays, the template becomes a bit more heavy: void foo(Range,Elem)(in Range range, Elem elem) if (isInputRange!Range && is(Elem : Unqual!(ElementType!Range))) { ... } I don't think I understand what you're showing here. How would I strip offthe const/immutable with a template ?Hmmm... * plays with is expressions * This seems to work: template UnConst(T) { static if (is(T t == const U, U)) // that is: 'if T is a 'const U', for some U' alias U UnConst; // then give me the U, (ie, T without a const) else alias T UnConst; // else give me the (original) T } template UnImmutable(T) { static if (is(T t == immutable U, U)) // 'if T is an 'immutable U', for some U' alias U UnImmutable; else alias T UnImmutable; } test: void main() { alias const int Int; writeln(UnConst!Int.stringof); writeln(Int.stringof); writeln(UnConst!int.stringof); writeln(UnConst!(const int).stringof); writeln(UnConst!(immutable int).stringof); alias immutable int IInt; writeln(UnConst!IInt.stringof); writeln(IInt.stringof); writeln(UnImmutable!int.stringof); writeln(UnImmutable!(const int).stringof); writeln(UnImmutable!(immutable int).stringof); } Philippe
Jun 28 2010
On Mon, 28 Jun 2010 08:14:12 -0400, Philippe Sigaud <philippe.sigaud gmail.com> wrote:On Mon, Jun 28, 2010 at 10:56, Jacob Carlborg <doob me.com> wrote: Something to keep in mind: as of 2.04x (.045? maybe), the way UTF-8 / UTF-32 is managed was changed. "asd" is an array of immutable(dchar), not imutable(char). At least DMD tells me that its element type is 'dchar'.No, that is not true. It's still an array of immutable(char). The compiler still sees it as an array of immutable(char). However, std.range forces the element type of char[] and wchar[] to be bidirectional ranges of dchar. The tests such as isRandomAccessRange and ElementType are fudged to say string is *not* a random access range, and its element type is dchar. This was one of Andrei's changes because without such shoehorning, std.algorithm could possible start shearing off strings that weren't valid. Whether that was the right decision remains to be seen. I personally would rather have special ranges that do those things. If I have a string that's always in English, why do I need to generate the dchars based on the characters in that array? -Steve
Jun 28 2010
On Mon, Jun 28, 2010 at 14:35, Steven Schveighoffer <schveiguy yahoo.com>wrote:On Mon, 28 Jun 2010 08:14:12 -0400, Philippe Sigaud < philippe.sigaud gmail.com> wrote: On Mon, Jun 28, 2010 at 10:56, Jacob Carlborg <doob me.com> wrote:Ah yes, indeed, you're right.Something to keep in mind: as of 2.04x (.045? maybe), the way UTF-8 / UTF-32 is managed was changed. "asd" is an array of immutable(dchar), not imutable(char). At least DMD tells me that its element type is 'dchar'.No, that is not true. It's still an array of immutable(char). The compiler still sees it as an array of immutable(char). However, std.range forces the element type of char[] and wchar[] to be bidirectional ranges of dchar. The tests such as isRandomAccessRange and ElementType are fudged to say string is *not* a random access range, and its element type is dchar. This was one of Andrei's changes because without such shoehorning, std.algorithm could possible start shearing off strings that weren't valid.Whether that was the right decision remains to be seen. I personally would rather have special ranges that do those things. If I have a string that's always in English, why do I need to generate the dchars based on the characters in that array?All that I can say is that it instantly broke dozens of unit tests in my projects, which were using strings a simple random-access ranges. It took me 2 DMD releases to work my way uout of it. Maybe I should have a look at byCodeUnit or somesuch. But for clueless users like me, strings suddenly became much more complicated to use. Maybe I was using them in unsafe ways, I don't know. I just hope for a way to get my simple strings back.
Jun 28 2010
On 2010-06-28 14:14, Philippe Sigaud wrote:On Mon, Jun 28, 2010 at 10:56, Jacob Carlborg <doob me.com <mailto:doob me.com>> wrote: Something to keep in mind: as of 2.04x (.045? maybe), the way UTF-8 / UTF-32 is managed was changed. "asd" is an array of immutable(dchar), not imutable(char). At least DMD tells me that its element type is 'dchar'. So your function can be done this way in D2: void foo(T,U)(in T[] a, U b) if (is(U : Unqual!T)) // that compiles only if b can be cast to A { writeln(a,b); } "asd".foo('s'); // prints "asds". is(U == Unqual!T) does not work, for U is 'char' while Unqual!T is 'dchar'. More generally, using ranges and not arrays, the template becomes a bit more heavy: void foo(Range,Elem)(in Range range, Elem elem) if (isInputRange!Range && is(Elem : Unqual!(ElementType!Range))) { ... } I don't think I understand what you're showing here. How would I strip off the const/immutable with a template ? Hmmm... * plays with is expressions * This seems to work: template UnConst(T) { static if (is(T t == const U, U)) // that is: 'if T is a 'const U', for some U' alias U UnConst; // then give me the U, (ie, T without a const) else alias T UnConst; // else give me the (original) T } template UnImmutable(T) { static if (is(T t == immutable U, U)) // 'if T is an 'immutable U', for some U' alias U UnImmutable; else alias T UnImmutable; } test: void main() { alias const int Int; writeln(UnConst!Int.stringof); writeln(Int.stringof); writeln(UnConst!int.stringof); writeln(UnConst!(const int).stringof); writeln(UnConst!(immutable int).stringof); alias immutable int IInt; writeln(UnConst!IInt.stringof); writeln(IInt.stringof); writeln(UnImmutable!int.stringof); writeln(UnImmutable!(const int).stringof); writeln(UnImmutable!(immutable int).stringof); } PhilippeHmm, now I don't know what I'm doing, I thought you could do something like this: template Char (T) { alias T Char; } void foo (T) (Char!(T) b) { } void main () { foo('s'); } -- /Jacob Carlborg
Jun 28 2010
Hello Jacob,On 2010-06-28 02:28, BCS wrote:[...]One solution would be to have templates strip off const/immutable from the top level of args.I was proposing a language change Sorry for any confusion. The idea is that unless the user ask for it explicitly, there is no particular reason to preserve const/immutable for the value portion (true value types and the first level of references/pointers) of arguments. -- ... <IXOYE><This solution would match the proposal that popped up a while ago to allow value assignment from const/immutable to mutable.I don't think I understand what you're showing here. How would I strip off the const/immutable with a template ?
Jun 28 2010
On 2010-06-28 15:48, BCS wrote:Hello Jacob,Ok, now I understand. -- /Jacob CarlborgOn 2010-06-28 02:28, BCS wrote:[...]One solution would be to have templates strip off const/immutable from the top level of args.I was proposing a language change Sorry for any confusion. The idea is that unless the user ask for it explicitly, there is no particular reason to preserve const/immutable for the value portion (true value types and the first level of references/pointers) of arguments.This solution would match the proposal that popped up a while ago to allow value assignment from const/immutable to mutable.I don't think I understand what you're showing here. How would I strip off the const/immutable with a template ?
Jun 28 2010