• Peter Neubauer (13/13) Mar 29 2008 Is there a way to give default types to template tuple parameters?
• Simen Kjaeraas (13/26) Mar 30 2008 This oughtta work (does on my confuser).
• Peter Neubauer (9/49) Mar 30 2008 Strange, all I get is this:
• Simen Kjaeraas (9/51) Mar 30 2008 Tested it again. Appears I did get part of it wrong.

Peter Neubauer <peterneubauer2 gmail.com> writes:

Is there a way to give default types to template tuple parameters?
Like this:


class Test (TTuple ... = [char, int] )
{
	// ...
}

void main ()
{
	Test t; // Equivalent to Test !(char, int) t;
}


Obviously, that does not compile.

Thanks in advance,
-Peter

"Simen Kjaeraas" <simen.kjaras gmail.com> writes:

On Sun, 30 Mar 2008 06:06:00 +0200, Peter Neubauer  =

<peterneubauer2 gmail.com> wrote:

 Is there a way to give default types to template tuple parameters?
 Like this:


 class Test (TTuple ... =3D [char, int] )
 {
 	// ...
 }

 void main ()
 {
 	Test t; // Equivalent to Test !(char, int) t;
 }


 Obviously, that does not compile.

 Thanks in advance,
 -Peter

This oughtta work (does on my confuser).


   import std.typetuple;

   class Test (TTuple ... =3D TypeTuple!(char, int) )
   {
	// ...
   }

   void main ()
   {
	Test t; // Equivalent to Test !(char, int) t;
   }


-- Simen

Peter Neubauer <peterneubauer2 gmail.com> writes:

Simen Kjaeraas schrieb:
 On Sun, 30 Mar 2008 06:06:00 +0200, Peter Neubauer 
 <peterneubauer2 gmail.com> wrote:
 
 Is there a way to give default types to template tuple parameters?
 Like this:


 class Test (TTuple ... = [char, int] )
 {
     // ...
 }

 void main ()
 {
     Test t; // Equivalent to Test !(char, int) t;
 }


 Obviously, that does not compile.

 Thanks in advance,
 -Peter

 
 This oughtta work (does on my confuser).
 
 
   import std.typetuple;
 
   class Test (TTuple ... = TypeTuple!(char, int) )
   {
     // ...
   }
 
   void main ()
   {
     Test t; // Equivalent to Test !(char, int) t;
   }
 
 
 -- Simen

Strange, all I get is this:

test.d(3): found '=' when expecting ')'
test.d(3): { } expected following aggregate declaration
test.d(3): no identifier for declarator TypeTuple!(char,int)
test.d(3): semicolon expected, not ')'
test.d(3): Declaration expected, not ')'

Maybe this is a difference between D 1.0 and 2.0? (I'm using 1.0)

-Peter

"Simen Kjaeraas" <simen.kjaras gmail.com> writes:

On Mon, 31 Mar 2008 01:29:10 +0200, Peter Neubauer  =

<peterneubauer2 gmail.com> wrote:

 Simen Kjaeraas schrieb:
 On Sun, 30 Mar 2008 06:06:00 +0200, Peter Neubauer  =


 <peterneubauer2 gmail.com> wrote:

 Is there a way to give default types to template tuple parameters?
 Like this:


 class Test (TTuple ... =3D [char, int] )
 {
     // ...
 }

 void main ()
 {
     Test t; // Equivalent to Test !(char, int) t;
 }


 Obviously, that does not compile.

 Thanks in advance,
 -Peter

  This oughtta work (does on my confuser).
     import std.typetuple;
    class Test (TTuple ... =3D TypeTuple!(char, int) )
   {
     // ...
   }
    void main ()
   {
     Test t; // Equivalent to Test !(char, int) t;
   }
   -- Simen

 Strange, all I get is this:

 test.d(3): found '=3D' when expecting ')'
 test.d(3): { } expected following aggregate declaration
 test.d(3): no identifier for declarator TypeTuple!(char,int)
 test.d(3): semicolon expected, not ')'
 test.d(3): Declaration expected, not ')'

 Maybe this is a difference between D 1.0 and 2.0? (I'm using 1.0)

 -Peter


Tested it again. Appears I did get part of it wrong.

	class test(TTuple =3D TypeTuple!(char, int))

That works. Without the ellipsis. However, that is of course not what yo=
u  =

wanted.
I do agree it should, though.

--Simen