## digitalmars.D.learn - Sum a lot of numbers...

• Alexandre (6/6) Jul 10 2014 Hi :)
• Alexandre (20/26) Jul 10 2014 PS: that is my code:
• Justin Whear (2/10) Jul 10 2014 A full decimal representation can be gotten with `format("%f", n);`
• Justin Whear (4/16) Jul 10 2014 And if you need more than the default 6 digits of precision after the
```Hi :)

I need to sum a list of numbers... but, when I calculate the sum
of this numbers, I got a simplify representation of sum:

2.97506e+,12

How I can make to get the correctly representation of this number
?
```
Jul 10 2014
```PS: that is my code:

import std.stdio, std.algorithm, std.range, std.conv;

string InsertComma(string val)
{
return val[0 .. \$-2] ~ "," ~ val[\$-2 .. \$];
}

int main(string[] argv)
{
auto x = "oi.txt"
.File
.byLine
.filter!(line => line == '1')
.map!(line => line[127 .. 140].to!real)
.sum;

auto valor = to!string(x);

write(InsertComma(valor));

return 0;
}

On Thursday, 10 July 2014 at 17:16:01 UTC, Alexandre wrote:
Hi :)

I need to sum a list of numbers... but, when I calculate the
sum of this numbers, I got a simplify representation of sum:

2.97506e+,12

How I can make to get the correctly representation of this
number ?

```
Jul 10 2014
```On Thu, 10 Jul 2014 17:16:00 +0000, Alexandre wrote:

Hi :)

I need to sum a list of numbers... but, when I calculate the sum of this
numbers, I got a simplify representation of sum:

2.97506e+,12

How I can make to get the correctly representation of this number ?

A full decimal representation can be gotten with `format("%f", n);`
```
Jul 10 2014
```On Thu, 10 Jul 2014 17:17:40 +0000, Justin Whear wrote:

On Thu, 10 Jul 2014 17:16:00 +0000, Alexandre wrote:

Hi :)

I need to sum a list of numbers... but, when I calculate the sum of
this numbers, I got a simplify representation of sum:

2.97506e+,12

How I can make to get the correctly representation of this number ?

A full decimal representation can be gotten with `format("%f", n);`

And if you need more than the default 6 digits of precision after the
decimal, you can use a precision specifier, e.g. for 10 digits: `format
("%.10f", n)`
```
Jul 10 2014