• AlphaPurned (5/5) Feb 20 2020 std.regex.split(l, ctRegex!`[\s-\)\(\.]`);
• =?UTF-8?Q?Ali_=c3=87ehreli?= (21/25) Feb 20 2020 It turns out, split uses splitter, which is more capable, like allowing
• =?UTF-8?Q?Ali_=c3=87ehreli?= (6/8) Feb 20 2020 After realizing that No.keepSeparators is the default value anyway, I=20

AlphaPurned <Alpha Beta.com> writes:

std.regex.split(l, ctRegex!`[\s-\)\(\.]`);

I'm trying too split a string on spaces and stuff... but it is 
returning empty strings and other matches(e.g., ()).

I realize I can delete afterwards but is there a direct way from 
split or ctRegex?

=?UTF-8?Q?Ali_=c3=87ehreli?= <acehreli yahoo.com> writes:

On 2/20/20 2:02 PM, AlphaPurned wrote:> std.regex.split(l, 
ctRegex!`[\s-\)\(\.]`);
 I'm trying too split a string on spaces and stuff... but it is returning
 empty strings and other matches(e.g., ()).

 I realize I can delete afterwards but is there a direct way from split
 or ctRegex?

It turns out, split uses splitter, which is more capable, like allowing 
to say "do not keep the separators". The difference is, splitter returns 
a range, so I called .array to give you an array but it's not necessary.

I took liberty to add a '+' to your pattern, which may not be useful in 
your case:

import std.regex;
import std.stdio;
import std.typecons : No, Yes;
import std.array;

void main() {
   auto l = "hello world\t  and  moon";
   auto range = std.regex.splitter!(No.keepSeparators)(l, 
ctRegex!`[\s-\)\(\.]+`);
   auto array = range.array;

   writeln(range);
   writeln(array);
}

Both lines print ["hello", "world", "and", "moon"].

Ali

=?UTF-8?Q?Ali_=c3=87ehreli?= <acehreli yahoo.com> writes:

On 2/20/20 4:46 PM, Ali =C3=87ehreli wrote:

    auto range =3D std.regex.splitter!(No.keepSeparators)(l,
 ctRegex!`[\s-\)\(\.]+`);

After realizing that No.keepSeparators is the default value anyway, I=20
tried 'split' and it worked the way you wanted. So, perhaps all you=20
needed was that extra '+' in the regex pattern:

   std.regex.split(l, ctRegex!`[\s-\)\(\.]+`)

Ali