• biocyberman (3/3) Jun 23 2018 I get the same output with or without "g" flag at line 6:
• Basile B. (10/13) Jun 23 2018 My bet is that Regex results in D are lazy so "g" doesn't make
• biocyberman (4/22) Jun 23 2018 I should have read the doc more thoroughly:

biocyberman <biocyberman gmail.com> writes:

I get the same output with or without "g" flag at line 6:
https://run.dlang.io/is/9n7iz6

So I don't understand when I have to use "g" flag.

Basile B. <b2.temp gmx.com> writes:

On Saturday, 23 June 2018 at 12:17:08 UTC, biocyberman wrote:
 I get the same output with or without "g" flag at line 6:
 https://run.dlang.io/is/9n7iz6

 So I don't understand when I have to use "g" flag.

My bet is that Regex results in D are lazy so "g" doesn't make 
sense in this context however I'm able to see an effect with 
"match":

match("12000 + 42100 = 54100", regex(r"(?<=\d)(?=(\d\d\d)+\b)", 
"")).writeln;
match("12000 + 42100 = 54100", regex(r"(?<=\d)(?=(\d\d\d)+\b)", 
"g")).writeln;

matchFirst would be like without "g"
matchAll would be like with "g"

biocyberman <biocyberman gmail.com> writes:

On Saturday, 23 June 2018 at 13:45:32 UTC, Basile B. wrote:
 On Saturday, 23 June 2018 at 12:17:08 UTC, biocyberman wrote:
 I get the same output with or without "g" flag at line 6:
 https://run.dlang.io/is/9n7iz6

 So I don't understand when I have to use "g" flag.

 My bet is that Regex results in D are lazy so "g" doesn't make 
 sense in this context however I'm able to see an effect with 
 "match":

 match("12000 + 42100 = 54100", regex(r"(?<=\d)(?=(\d\d\d)+\b)", 
 "")).writeln;
 match("12000 + 42100 = 54100", regex(r"(?<=\d)(?=(\d\d\d)+\b)", 
 "g")).writeln;

 matchFirst would be like without "g"
 matchAll would be like with "g"

I should have read the doc more thoroughly:

https://dlang.org/phobos/std_regex.html#match
Delegating the kind of operation to "g" flag is soon to be 
phased out along with the ability to choose the exact matching 
scheme.

So case closed for me