• ParticlePeter (14/14) May 23 2016 alias uint32_t = uint;
• Rene Zwanenburg (5/6) May 23 2016 Nope. For the compiler uint32_t and uint are the same thing, this

ParticlePeter <ParticlePeter gmx.de> writes:

alias uint32_t = uint;

struct Offset() {
   uint32_t x;
   uint32_t y;
}

// Introspect with:

void printStructInfo( T )( T info ) {
   import std.stdio : writefln;
   foreach (memb; __traits(allMembers, T)) {
     writefln(typeof(__traits(getMember, info, memb)).stringof);
   }
}

// Result is uint

Is there a way to get the alias uint32_t instead ?

Rene Zwanenburg <renezwanenburg gmail.com> writes:

On Monday, 23 May 2016 at 10:45:49 UTC, ParticlePeter wrote:
 Is there a way to get the alias uint32_t instead ?

Nope. For the compiler uint32_t and uint are the same thing, this 
is by design. Typedef can be used to create a separate type with 
the same semantics as the type it's based upon:

https://dlang.org/phobos/std_typecons.html#.Typedef