• Nick (6/6) Jan 25 2011 Instead of mixing in type by type, is there a way to mixin a Type Tuple?...
• Philippe Sigaud (4/8) Jan 25 2011 Could you give an example of type mixin? I'm not sure I understand
• Simen kjaeraas (11/15) Jan 25 2011 That would be the way to do it, yes:
• Nick (7/21) Feb 19 2011 Thanks! The problem is with mixing containing identical members. Then I

Nick <nick example.com> writes:

Instead of mixing in type by type, is there a way to mixin a Type Tuple? 
Some foreach Type mixin;

Otherwise, I guess recursive templated inheritance with a single mixin 
at each level should to the trick?

Thanks,
Nick

Philippe Sigaud <philippe.sigaud gmail.com> writes:

On Tue, Jan 25, 2011 at 12:33, Nick <nick example.com> wrote:
 Instead of mixing in type by type, is there a way to mixin a Type Tuple?
 Some foreach Type mixin;

 Otherwise, I guess recursive templated inheritance with a single mixin at
 each level should to the trick?

Could you give an example of type mixin? I'm not sure I understand
what you're trying to do.

Philippe

"Simen kjaeraas" <simen.kjaras gmail.com> writes:

Nick <nick example.com> wrote:

 Instead of mixing in type by type, is there a way to mixin a Type Tuple?  
 Some foreach Type mixin;

 Otherwise, I guess recursive templated inheritance with a single mixin  
 at each level should to the trick?

That would be the way to do it, yes:

template chainedMixin( alias head, tail... ) {
     mixin head;
     mixin chainedMixin!tail;
}

template chainedMixin( alias head ) {
     mixin head;
}

-- 
Simen

Nick <nick example.com> writes:

On 1/25/2011 11:33 PM, Simen kjaeraas wrote:
 Nick <nick example.com> wrote:

 Instead of mixing in type by type, is there a way to mixin a Type
 Tuple? Some foreach Type mixin;

 Otherwise, I guess recursive templated inheritance with a single mixin
 at each level should to the trick?

 That would be the way to do it, yes:

 template chainedMixin( alias head, tail... ) {
 mixin head;
 mixin chainedMixin!tail;
 }

 template chainedMixin( alias head ) {
 mixin head;
 }

Thanks! The problem is with mixing containing identical members. Then I 
need to disambiguate to address them. For that, I'd need to say 
something like

mixin head headIdentifier;

But I would need to differentiate somehow those identifiers... Any ideas?

Thanks!