• Machine Code (4/4) Apr 16 2019 I've tried those syntaxes:
• Adam D. Ruppe (6/7) Apr 16 2019 appender isn't a type, it is a helper function that returns a
• Machine Code (2/9) Apr 16 2019 I see. Thank you!

Machine Code <jckj33 gmail.com> writes:

I've tried those syntaxes:

void f(appender!string buffer) { }
void f(A = appender)(A!string buffer) { }

but no luck... how do I do that?

Adam D. Ruppe <destructionator gmail.com> writes:

On Tuesday, 16 April 2019 at 21:07:51 UTC, Machine Code wrote:
 void f(appender!string buffer) { }

appender isn't a type, it is a helper function that returns a 
type called Appender:

http://dpldocs.info/experimental-docs/std.array.appender.1.html

http://dpldocs.info/experimental-docs/std.array.Appender.html



So try like `void f(Appender!string buffer) {}`

Machine Code <jckj33 gmail.com> writes:

On Tuesday, 16 April 2019 at 21:24:54 UTC, Adam D. Ruppe wrote:
 On Tuesday, 16 April 2019 at 21:07:51 UTC, Machine Code wrote:
 void f(appender!string buffer) { }

 appender isn't a type, it is a helper function that returns a 
 type called Appender:

 http://dpldocs.info/experimental-docs/std.array.appender.1.html

 http://dpldocs.info/experimental-docs/std.array.Appender.html



 So try like `void f(Appender!string buffer) {}`

I see. Thank you!