digitalmars.D.learn - How can I convert the following C to D.

anon (10/10) Jan 21 2015 I have the following C code, how can I do the same in D.

ketmar via Digitalmars-d-learn (3/16) Jan 21 2015 this is not C.

anon (3/20) Jan 21 2015 Your right its c++

ketmar via Digitalmars-d-learn (5/27) Jan 21 2015 so the answer to your question is very easy: just type in any

anon (10/39) Jan 21 2015 Great answer.

bearophile (5/8) Jan 21 2015 That's probably a better and simpler translation. I have tried to

bearophile (32/41) Jan 21 2015 I suggest you to ignore ketmar, he's not helping :-)

anon (5/48) Jan 21 2015 Hi Bearophile,

bearophile (4/5) Jan 21 2015 But what's the purpose of the last two empty arrays?

anonymous (31/41) Jan 21 2015 The super-literal translation:

"anon" <anon spam.com> writes:

I have the following C code, how can I do the same in D.

Info **info;
info = new Info*[hl + 2];

int r;
for(r = 0; r < hl; r++)
{
	info[r] = new Info[vl + 2];
}
info[r] = NULL;

anon

Jan 21 2015

ketmar via Digitalmars-d-learn <digitalmars-d-learn puremagic.com> writes:

On Wed, 21 Jan 2015 23:44:49 +0000
anon via Digitalmars-d-learn <digitalmars-d-learn puremagic.com> wrote:

 I have the following C code, how can I do the same in D.
=20
 Info **info;
 info =3D new Info*[hl + 2];
=20
 int r;
 for(r =3D 0; r < hl; r++)
 {
 	info[r] =3D new Info[vl + 2];
 }
 info[r] =3D NULL;
=20
 anon

this is not C.

Jan 21 2015

"anon" <anon spam.com> writes:

On Wednesday, 21 January 2015 at 23:47:46 UTC, ketmar via 
Digitalmars-d-learn wrote:
 On Wed, 21 Jan 2015 23:44:49 +0000
 anon via Digitalmars-d-learn 
 <digitalmars-d-learn puremagic.com> wrote:

 I have the following C code, how can I do the same in D.
 
 Info **info;
 info = new Info*[hl + 2];
 
 int r;
 for(r = 0; r < hl; r++)
 {
 	info[r] = new Info[vl + 2];
 }
 info[r] = NULL;
 
 anon

 this is not C.

Your right its c++

Jan 21 2015

ketmar via Digitalmars-d-learn <digitalmars-d-learn puremagic.com> writes:

On Wed, 21 Jan 2015 23:50:59 +0000
anon via Digitalmars-d-learn <digitalmars-d-learn puremagic.com> wrote:

 On Wednesday, 21 January 2015 at 23:47:46 UTC, ketmar via=20
 Digitalmars-d-learn wrote:
 On Wed, 21 Jan 2015 23:44:49 +0000
 anon via Digitalmars-d-learn=20
 <digitalmars-d-learn puremagic.com> wrote:

 I have the following C code, how can I do the same in D.
=20
 Info **info;
 info =3D new Info*[hl + 2];
=20
 int r;
 for(r =3D 0; r < hl; r++)
 {
 	info[r] =3D new Info[vl + 2];
 }
 info[r] =3D NULL;
=20
 anon

 this is not C.

=20
 Your right its c++

so the answer to your question is very easy: just type in any
gibberish. as C cannot compile C++ code, the final result is to get the
code that cannot be compiled. any gibberish will do.

Jan 21 2015

"anon" <anon spam.com> writes:

On Wednesday, 21 January 2015 at 23:59:34 UTC, ketmar via 
Digitalmars-d-learn wrote:
 On Wed, 21 Jan 2015 23:50:59 +0000
 anon via Digitalmars-d-learn 
 <digitalmars-d-learn puremagic.com> wrote:

 On Wednesday, 21 January 2015 at 23:47:46 UTC, ketmar via 
 Digitalmars-d-learn wrote:
 On Wed, 21 Jan 2015 23:44:49 +0000
 anon via Digitalmars-d-learn 
 <digitalmars-d-learn puremagic.com> wrote:

 I have the following C code, how can I do the same in D.
 
 Info **info;
 info = new Info*[hl + 2];
 
 int r;
 for(r = 0; r < hl; r++)
 {
 	info[r] = new Info[vl + 2];
 }
 info[r] = NULL;
 
 anon

 this is not C.

 
 Your right its c++

 so the answer to your question is very easy: just type in any
 gibberish. as C cannot compile C++ code, the final result is to 
 get the
 code that cannot be compiled. any gibberish will do.

Great answer.

Anyway the code isn't mine I just wanted to know how to handle 
what the author wrote.

I got it working with.

auto info = new Info[][](hl, vl);

and changing the logic so as not check for the NULL.

No need on being picky it was just a question.

anon

Jan 21 2015

"bearophile" <bearophileHUGS lycos.com> writes:

anon:

 I got it working with.

 auto info = new Info[][](hl, vl);

 and changing the logic so as not check for the NULL.

That's probably a better and simpler translation. I have tried to 
translate your original code too much literally.

Bye,
bearophile

Jan 21 2015

"bearophile" <bearophileHUGS lycos.com> writes:

anon:

 I have the following C code, how can I do the same in D.

 Info **info;
 info = new Info*[hl + 2];

 int r;
 for(r = 0; r < hl; r++)
 {
 	info[r] = new Info[vl + 2];
 }
 info[r] = NULL;

I suggest you to ignore ketmar, he's not helping :-)

Is your code initializing info[r+1]?

This is roughly a D translation (untested):


void main()  safe {
     import std.stdio;

     enum uint hl = 5;
     enum uint vl = 7;
     static struct Info {}

     auto info = new Info[][](hl + 2);

     foreach (ref r; info[0 .. hl])
         r = new Info[vl + 2];

     writefln("[\n%(%s,\n%)\n]", info);
}


Output:

[
[Info(), Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
Info()],
[Info(), Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
Info()],
[Info(), Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
Info()],
[Info(), Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
Info()],
[Info(), Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
Info()],
[],
[]
]


Is this what you look for?

Bye,
bearophile

Jan 21 2015

"anon" <anon spam.com> writes:

On Thursday, 22 January 2015 at 00:16:23 UTC, bearophile wrote:
 anon:

 I have the following C code, how can I do the same in D.

 Info **info;
 info = new Info*[hl + 2];

 int r;
 for(r = 0; r < hl; r++)
 {
 	info[r] = new Info[vl + 2];
 }
 info[r] = NULL;

 I suggest you to ignore ketmar, he's not helping :-)

 Is your code initializing info[r+1]?

 This is roughly a D translation (untested):


 void main()  safe {
     import std.stdio;

     enum uint hl = 5;
     enum uint vl = 7;
     static struct Info {}

     auto info = new Info[][](hl + 2);

     foreach (ref r; info[0 .. hl])
         r = new Info[vl + 2];

     writefln("[\n%(%s,\n%)\n]", info);
 }


 Output:

 [
 [Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
 Info(), Info()],
 [Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
 Info(), Info()],
 [Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
 Info(), Info()],
 [Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
 Info(), Info()],
 [Info(), Info(), Info(), Info(), Info(), Info(), Info(), 
 Info(), Info()],
 [],
 []
 ]


 Is this what you look for?

 Bye,
 bearophile

Hi Bearophile,

It looks like what I need.

Thanks,
anon

Jan 21 2015

"bearophile" <bearophileHUGS lycos.com> writes:

anon:

 It looks like what I need.

But what's the purpose of the last two empty arrays?

Bye,
bearophile

Jan 21 2015

"anonymous" <anonymous example.com> writes:

On Wednesday, 21 January 2015 at 23:44:52 UTC, anon wrote:
 I have the following C code, how can I do the same in D.

 Info **info;
 info = new Info*[hl + 2];

 int r;
 for(r = 0; r < hl; r++)
 {
 	info[r] = new Info[vl + 2];
 }
 info[r] = NULL;

 anon

The super-literal translation:
     Info** info;
     info = new Info*[hl + 2].ptr;
     int r;
     for(r = 0; r < hl; r++)
     {
         info[r] = new Info[vl + 2].ptr;
     }
     info[r] = null;

A little more D-ish:
     Info[][] info = new Info[][hl + 2];
     foreach(r; 0 .. hl)
     {
         info[r] = new Info[vl + 2];
     }
     assert(info[hl].length == 0); /* Relying on default 
initialization. */

D to the ultimate max:
     import std.algorithm;
     import std.range;
     auto info = iota(hl)
         .map!(i => new Info[vl + 2])
         .chain(only(Info[].init, Info[].init))
         .array;
     static assert(is(typeof(info) == Info[][]));
     assert(info.length == hl + 2);
     assert(info[hl].empty);

And if those +2 are for sentinel values, D doesn't need them 
because D arrays know their length. And it all comes down to:
     auto info = new Info[][](hl, vl);

Jan 21 2015

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digitalmars.D.learn - How can I convert the following C to D.