• Joel (13/13) Dec 02 2018 I can't seem to get this to work!
• Nicholas Wilson (4/18) Dec 02 2018 https://run.dlang.io/is/h0ArAB
• Joel (3/8) Dec 02 2018 Oh, I was using std.algorithm's 'stripLeft' instead of
• Steven Schveighoffer (4/15) Dec 03 2018 Interesting. I can see the reason too -- there is no "should be

Joel <joelcnz gmail.com> writes:

I can't seem to get this to work!

```
foreach(line; File("help.txt").byLine) {
     writeln(line.stripLeft);
```

With the code above, I get this compile error:
source/app.d(360,36): Error: template 
std.algorithm.mutation.stripLeft cannot deduce function from 
argument types !()(char[]), candidates are:
/usr/local/opt/dmd/include/dlang/dmd/std/algorithm/mutation.d(2602,7):       
std.algorithm.mutation.stripLeft(Range, E)(Range range, E element) if
(isInputRange!Range && is(typeof(range.front == element) : bool))
/usr/local/opt/dmd/include/dlang/dmd/std/algorithm/mutation.d(2610,7):       
std.algorithm.mutation.stripLeft(alias pred, Range)(Range range) if
(isInputRange!Range && is(typeof(pred(range.front)) : bool))

I just want to use each 'line' variable as a string?! I've tried 
'byLineCopy', and 'line.to!string'. I've looked at documentation.

Nicholas Wilson <iamthewilsonator hotmail.com> writes:

On Monday, 3 December 2018 at 06:09:21 UTC, Joel wrote:
 I can't seem to get this to work!

 ```
 foreach(line; File("help.txt").byLine) {
     writeln(line.stripLeft);
 ```

 With the code above, I get this compile error:
 source/app.d(360,36): Error: template 
 std.algorithm.mutation.stripLeft cannot deduce function from 
 argument types !()(char[]), candidates are:
 /usr/local/opt/dmd/include/dlang/dmd/std/algorithm/mutation.d(2602,7):       
std.algorithm.mutation.stripLeft(Range, E)(Range range, E element) if
(isInputRange!Range && is(typeof(range.front == element) : bool))
 /usr/local/opt/dmd/include/dlang/dmd/std/algorithm/mutation.d(2610,7):       
std.algorithm.mutation.stripLeft(alias pred, Range)(Range range) if
(isInputRange!Range && is(typeof(pred(range.front)) : bool))

 I just want to use each 'line' variable as a string?! I've 
 tried 'byLineCopy', and 'line.to!string'. I've looked at 
 documentation.

https://run.dlang.io/is/h0ArAB

works for me. If you want it as a string not  char[] then 
byLineCopy should work, if not just `.idup` `line`.

Joel <joelcnz gmail.com> writes:

On Monday, 3 December 2018 at 06:55:50 UTC, Nicholas Wilson wrote:
 On Monday, 3 December 2018 at 06:09:21 UTC, Joel wrote:
 [...]

 https://run.dlang.io/is/h0ArAB

 works for me. If you want it as a string not  char[] then 
 byLineCopy should work, if not just `.idup` `line`.

Oh, I was using std.algorithm's 'stripLeft' instead of 
std.string's 'stripLeft'.

Steven Schveighoffer <schveiguy gmail.com> writes:

On 12/3/18 2:03 AM, Joel wrote:
 On Monday, 3 December 2018 at 06:55:50 UTC, Nicholas Wilson wrote:
 On Monday, 3 December 2018 at 06:09:21 UTC, Joel wrote:
 [...]

 https://run.dlang.io/is/h0ArAB

 works for me. If you want it as a string not  char[] then byLineCopy 
 should work, if not just `.idup` `line`.

 
 Oh, I was using std.algorithm's 'stripLeft' instead of std.string's 
 'stripLeft'.

Interesting. I can see the reason too -- there is no "should be 
stripped" property for all types, just character types (is it a space).

-Steve