• Narxa (15/15) Dec 11 2018 Hello, people!
• Adam D. Ruppe (4/5) Dec 11 2018 You can just cast it to float:
• Narxa (6/11) Dec 11 2018 It produced the following error:
• Steven Schveighoffer (3/20) Dec 11 2018 You need to cast the result back to int.
• Narxa (7/28) Dec 11 2018 Yes, it worked:
• Andrea Fontana (8/13) Dec 11 2018 I think you don't need floor.

Narxa <fbf99eQrXpHcjP8L gmail.com> writes:

Hello, people!


The following case:
-------------------
int var = floor(sqrt(n)) // where 'n' is a 'const int'

Produces the following error:
-----------------------------
Error: std.math.sqrt called with argument types (const(int)) 
matches both:
/usr/include/dmd/phobos/std/math.d(2067):     std.math.sqrt(float 
x)
and:
/usr/include/dmd/phobos/std/math.d(2073):     std.math.sqrt(real 
x)


Please, could you tell me how do I solve this?!

Thank you!

Adam D. Ruppe <destructionator gmail.com> writes:

On Tuesday, 11 December 2018 at 14:16:05 UTC, Narxa wrote:
 int var = floor(sqrt(n)) // where 'n' is a 'const int'

You can just cast it to float:

floor(sqrt( cast(float) n ));

and it will work.

Narxa <fbf99eQrXpHcjP8L gmail.com> writes:

On Tuesday, 11 December 2018 at 14:22:30 UTC, Adam D. Ruppe wrote:
 On Tuesday, 11 December 2018 at 14:16:05 UTC, Narxa wrote:
 int var = floor(sqrt(n)) // where 'n' is a 'const int'

 You can just cast it to float:

 floor(sqrt( cast(float) n ));

 and it will work.

It produced the following error:
--------------------------------
Error: cannot implicitly convert expression 
floor(sqrt(cast(float)n)) of type float to int


I am using 'dmd' compiler if it matters.

Steven Schveighoffer <schveiguy gmail.com> writes:

On 12/11/18 9:47 AM, Narxa wrote:
 On Tuesday, 11 December 2018 at 14:22:30 UTC, Adam D. Ruppe wrote:
 On Tuesday, 11 December 2018 at 14:16:05 UTC, Narxa wrote:
 int var = floor(sqrt(n)) // where 'n' is a 'const int'

 You can just cast it to float:

 floor(sqrt( cast(float) n ));

 and it will work.

 
 It produced the following error:
 --------------------------------
 Error: cannot implicitly convert expression floor(sqrt(cast(float)n)) of 
 type float to int
 
 
 I am using 'dmd' compiler if it matters.

You need to cast the result back to int.

-Steve

Narxa <fbf99eQrXpHcjP8L gmail.com> writes:

On Tuesday, 11 December 2018 at 14:53:02 UTC, Steven 
Schveighoffer wrote:
 On 12/11/18 9:47 AM, Narxa wrote:
 On Tuesday, 11 December 2018 at 14:22:30 UTC, Adam D. Ruppe 
 wrote:
 On Tuesday, 11 December 2018 at 14:16:05 UTC, Narxa wrote:
 int var = floor(sqrt(n)) // where 'n' is a 'const int'

 You can just cast it to float:

 floor(sqrt( cast(float) n ));

 and it will work.

 
 It produced the following error:
 --------------------------------
 Error: cannot implicitly convert expression 
 floor(sqrt(cast(float)n)) of type float to int
 
 
 I am using 'dmd' compiler if it matters.

 You need to cast the result back to int.

 -Steve

Yes, it worked:
---------------
int var = cast(int) floor(sqrt( cast(float) n ));


I thought floor already returned an 'int' but I was mistaken.

Thank you very much.

Andrea Fontana <nospam example.org> writes:

On Tuesday, 11 December 2018 at 15:17:10 UTC, Narxa wrote:
 Yes, it worked:
 ---------------
 int var = cast(int) floor(sqrt( cast(float) n ));


 I thought floor already returned an 'int' but I was mistaken.

 Thank you very much.

I think you don't need floor.

int var = cast(int)(sqrt(cast(float)n));

or:

int var = cast(int)(float(i).sqrt);

or:

int var = float(i).sqrt.to!int;

Andrea