• ParticlePeter (6/6) Jun 17 2015 I use wrapper functions taking void[] arrays to forward them
• Alex Parrill (2/8) Jun 17 2015 Try slicing it: `array[]`
• ParticlePeter (4/12) Jun 17 2015 That gives me a range, which I could convert to an array with
• "Marc =?UTF-8?B?U2Now7x0eiI=?= <schuetzm gmx.net> (3/9) Jun 17 2015 Would this work?
• ParticlePeter (5/14) Jun 17 2015 Unfortunately not:
• Kagamin (1/1) Jun 17 2015 (&arr.front())[0 .. arr.length] ?
• ParticlePeter (2/3) Jun 17 2015 Yes, this works, nice, thanks :-)

"ParticlePeter" <ParticlePeter gmx.de> writes:

I use wrapper functions taking void[] arrays to forward them 
comfortably to mentioned OpenGL functions. This works with static 
and dynamic build in arrays, but I don't see a way how I could 
access (cast) the raw data of a std.container.array to forward it 
to these wrapper functions. std.array(Range)(Range r) does a copy 
which I would like to avoid. Any advice ?

"Alex Parrill" <initrd.gz gmail.com> writes:

On Wednesday, 17 June 2015 at 13:04:28 UTC, ParticlePeter wrote:
 I use wrapper functions taking void[] arrays to forward them 
 comfortably to mentioned OpenGL functions. This works with 
 static and dynamic build in arrays, but I don't see a way how I 
 could access (cast) the raw data of a std.container.array to 
 forward it to these wrapper functions. std.array(Range)(Range 
 r) does a copy which I would like to avoid. Any advice ?

Try slicing it: `array[]`

"ParticlePeter" <ParticlePeter gmx.de> writes:

On Wednesday, 17 June 2015 at 13:07:11 UTC, Alex Parrill wrote:
 On Wednesday, 17 June 2015 at 13:04:28 UTC, ParticlePeter wrote:
 I use wrapper functions taking void[] arrays to forward them 
 comfortably to mentioned OpenGL functions. This works with 
 static and dynamic build in arrays, but I don't see a way how 
 I could access (cast) the raw data of a std.container.array to 
 forward it to these wrapper functions. std.array(Range)(Range 
 r) does a copy which I would like to avoid. Any advice ?

 Try slicing it: `array[]`

That gives me a range, which I could convert to an array with 
std.array(Range)(Range
r) which I want to avoid.

"Marc =?UTF-8?B?U2Now7x0eiI=?= <schuetzm gmx.net> writes:

On Wednesday, 17 June 2015 at 13:04:28 UTC, ParticlePeter wrote:
 I use wrapper functions taking void[] arrays to forward them 
 comfortably to mentioned OpenGL functions. This works with 
 static and dynamic build in arrays, but I don't see a way how I 
 could access (cast) the raw data of a std.container.array to 
 forward it to these wrapper functions. std.array(Range)(Range 
 r) does a copy which I would like to avoid. Any advice ?

Would this work?

(&arr.front)[0 .. arr.length]

"ParticlePeter" <ParticlePeter gmx.de> writes:

On Wednesday, 17 June 2015 at 13:31:21 UTC, Marc Schütz wrote:
 On Wednesday, 17 June 2015 at 13:04:28 UTC, ParticlePeter wrote:
 I use wrapper functions taking void[] arrays to forward them 
 comfortably to mentioned OpenGL functions. This works with 
 static and dynamic build in arrays, but I don't see a way how 
 I could access (cast) the raw data of a std.container.array to 
 forward it to these wrapper functions. std.array(Range)(Range 
 r) does a copy which I would like to avoid. Any advice ?

 Would this work?

 (&arr.front)[0 .. arr.length]

Unfortunately not:
Error: Vector!(float, 3) delegate() pure nothrow  property ref 
 safe cannot be sliced with []

Fyi, its an std.container.array!( gl3n.Vector!(float, 3) ) array.

"Kagamin" <spam here.lot> writes:

(&arr.front())[0 .. arr.length] ?

"ParticlePeter" <ParticlePeter gmx.de> writes:

On Wednesday, 17 June 2015 at 13:58:09 UTC, Kagamin wrote:
 (&arr.front())[0 .. arr.length] ?

Yes, this works, nice, thanks :-)