Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Updated On: 11-3-2021

Apne doubts clear karein ab Whatsapp par bhi. Try it now.

CLICK HERE

Loading DoubtNut Solution for you

Watch 1000+ concepts & tricky questions explained!

200+

11

Text Solution

Solution :

Take the particle plus the sphere as the system <br> a. Using conservation of linear momentum, the inear speed o the combined system v is given by <br> `mv_0=(M+m)v or, v=(mv_0)/(M+m)` ……..i <br> b. Next we shall use conservation angular momentum about the centre of mass, which is to be taken at the centre of the sphere `(Mgtgtm)` Angular momentum of the particle before collsion is `mv_0(h-R).` If the system rotates with angular speed `omega` after collision, the angular momentum of the system becomes <br> `(2/5MR^2+mR^2)omega` <br> Hence, `mv_0(h-R)=(2/5 M+m)R^2omega` <br> or, ` omega=(mv_0(h-R))/(2/5 M+m))R^2` <br> c. The sphere will start roling just after the colision if <br> `v=omegaR i.e. (mv_0)/(M+m)=(mv_0(h-R))/(2/5M+m)R)` <br> giving`h=((7/5M+2m)/(M+m))R=7/5R`.**Basic Property Of Rigid Body**

**Rigid Body Motion**

**Velocity And Acceleration Of A Point In Rotating Rigid Body In Pure Rotation**

**Relative Angular Velocity In Case Of A Rigid Body**

**Rotational And Translationa Motion Together**

**Rolling Motion**

**Moment Of Inertia Of Rigid Body**

**Uniform Rectangular Sheet**

**Triangular Lamina About Its Base**

**INERTIA OF SQUARE SHEET ABOUT IT'S DIAGONAL**