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digitalmars.D.bugs - [Issue 6305] New: String literals doesn't already have a 0 appended to them

reply d-bugmail puremagic.com writes:
http://d.puremagic.com/issues/show_bug.cgi?id=6305

           Summary: String literals doesn't already have a 0 appended to
                    them
           Product: D
           Version: D1
          Platform: Other
        OS/Version: Windows
            Status: NEW
          Severity: minor
          Priority: P2
         Component: DMD
        AssignedTo: nobody puremagic.com
        ReportedBy: verylonglogin.reg gmail.com


--- Comment #0 from Denis <verylonglogin.reg gmail.com> 2011-07-13 01:57:25 PDT
---
According to http://www.digitalmars.com/d/1.0/arrays.html#printf
"String literals already have a 0 appended to them"
But if we create static arrays, they are exactly one after another: 

import std.stdio;
const s1 = "abcd", s2 = "EFG", s3 = "h";
void main() {
    writefln("%s %s %s\n%s %s %s",
        s1, *(s1.ptr + s1.length), cast(int) *(s1.ptr + s1.length),
        s2, *(s2.ptr + s2.length), cast(int) *(s2.ptr + s2.length)
    );
}

Prints:
abcd E 69
EFG h 104

If I missed something, I think this "something" should be mentioned in
documentation near citation above.

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next sibling parent d-bugmail puremagic.com writes:
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Steven Schveighoffer <schveiguy yahoo.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |schveiguy yahoo.com


--- Comment #1 from Steven Schveighoffer <schveiguy yahoo.com> 2011-07-13
05:35:41 PDT ---
This seems to be windows-specific.  The exact code produces this output on
linux (as far back as 2.033, the earliest installed compiler I have):

abcd  0
EFG  0

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--- Comment #2 from Denis <verylonglogin.reg gmail.com> 2011-07-13 05:40:27 PDT
---
(In reply to comment #1)

 This seems to be windows-specific.  The exact code produces this output on
 linux (as far back as 2.033, the earliest installed compiler I have):
 
 abcd  0
 EFG  0


It is a D1 only issue.

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Steven Schveighoffer <schveiguy yahoo.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|schveiguy yahoo.com         |


--- Comment #3 from Steven Schveighoffer <schveiguy yahoo.com> 2011-07-13
05:58:14 PDT ---
Oops, sorry for the noise.

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Steven Schveighoffer <schveiguy yahoo.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|NEW                         |RESOLVED
                 CC|                            |schveiguy yahoo.com
         Resolution|                            |INVALID


--- Comment #4 from Steven Schveighoffer <schveiguy yahoo.com> 2011-07-13
12:22:48 PDT ---
Actually, I did have a D1 compiler laying around.  And I figured out the issue.

The issue is D1's type inference treats string literal types as char[N] where N
is a uint.  Note that D2's type inference treats string literals as
immutable(char)[].  So the issue is that you are not declaring a type, and D is
assuming you meant it to be a fixed-sized array.  So the literal *does* have a
zero, but it is copied into your declared fixed-sized arrays in the global
segment without the zero.

I figured it out by doing:

pragma(msg, typeof(s1).stringof);

which prints:
char[4u];

If you do this:

const string s1 = "abcd", s2 = "EFG", s3 = "h";

Then it works as you expect.

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