digitalmars.D.bugs - [Issue 5800] New: Wrong NAN bit pattern during array initialization
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http://d.puremagic.com/issues/show_bug.cgi?id=5800
Summary: Wrong NAN bit pattern during array initialization
Product: D
Version: D2
Platform: Other
OS/Version: Linux
Status: NEW
Severity: normal
Priority: P2
Component: DMD
AssignedTo: nobody puremagic.com
ReportedBy: acehreli yahoo.com
Environment: dmd 2.052, 64-bit Ubuntu.
The following program passes the two asserts, showing that the array elements
are not initialized as NANs. The dumpBytes() function shows that the bit
pattern is different than a local variable's:
import std.stdio;
void main()
{
double[1] a;
auto myNaN = double.nan;
assert (a[0] != myNaN); // <-- passes; BUG
assert (a[0] != double.nan); // <-- passes; BUG
dumpBytes(a[0]);
dumpBytes(myNaN);
}
void dumpBytes(T)(ref T var)
{
const ubyte * beg = cast(ubyte*)&var;
foreach (bayt; beg .. beg + T.sizeof) {
writef("%02x ", *bayt);
}
writeln();
}
The bug manifests itself for float and real as well and the bit pattern changes
depending on whether -m32 or -m64 is used. Here is one output of the program
with -m64:
00 00 00 00 00 00 fc 7f
00 00 00 00 00 00 f8 7f
Ali
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kennytm gmail.com changed:
What |Removed |Added
----------------------------------------------------------------------------
CC| |kennytm gmail.com
Isn't it expected that 'nan' does not equate to itself?
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Ali Cehreli <acehreli yahoo.com> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|NEW |RESOLVED
Resolution| |INVALID
My mistake: "Equality Expressions" at
http://digitalmars.com/d/2.0/expression.html says "If either or both operands
are NAN, then both the == returns false and != returns true." [sic]
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