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digitalmars.D.bugs - [Issue 1179] New: Compiler doesn't complain about function redefinition when using template mixin

reply d-bugmail puremagic.com writes:
http://d.puremagic.com/issues/show_bug.cgi?id=1179

           Summary: Compiler doesn't complain about function redefinition
                    when using template mixin
           Product: D
           Version: 1.013
          Platform: PC
        OS/Version: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD
        AssignedTo: bugzilla digitalmars.com
        ReportedBy: aarti interia.pl


import std.stdio;
template t(T) {
    int policy() { return 1; }
}
class C {
    mixin t!(C);
    int policy() { return 2; }
}

void main() {
    writefln((new C).policy);
}


--
Apr 23 2007
parent reply d-bugmail puremagic.com writes:
http://d.puremagic.com/issues/show_bug.cgi?id=1179


bugzilla digitalmars.com changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|NEW                         |RESOLVED
         Resolution|                            |INVALID




------- Comment #1 from bugzilla digitalmars.com  2007-04-23 14:04 -------
This is the way its supposed to work. Each mixin gets its own namespace, so
that names can match names in the non-mixin declarations and other mixin
declarations. You can access those conflicting names by using the mixin name as
a scope operator.


--
Apr 23 2007
parent Aarti_pl <aarti interia.pl> writes:
d-bugmail puremagic.com napisał(a):

 http://d.puremagic.com/issues/show_bug.cgi?id=1179
 
 
 bugzilla digitalmars.com changed:
 
            What    |Removed                     |Added
 ----------------------------------------------------------------------------
              Status|NEW                         |RESOLVED
          Resolution|                            |INVALID
 
 
 
 
 ------- Comment #1 from bugzilla digitalmars.com  2007-04-23 14:04 -------
 This is the way its supposed to work. Each mixin gets its own namespace, so
 that names can match names in the non-mixin declarations and other mixin
 declarations. You can access those conflicting names by using the mixin name as
 a scope operator.
 
 


Probably below cite would be more appropriate to describe why my bug was 
invalid:  :-))  (I don't know any way to access anonymous mixin members 
- if there is a way to do it I would be happy to know how...)

---
Mixin Scope
The declarations in a mixin are 'imported' into the surrounding scope. 
If the name of a declaration in a mixin is the same as a declaration in 
the surrounding scope, the surrounding declaration overrides the mixin one.
---

Sorry about invalid bug report. Something strange is happening with 
mixins in my program, so I thought that it was reason. But it must be 
something else. I will try to find it out and report in another bug report.
Apr 24 2007