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digitalmars.D - Why is the "in" storage class missing from the ParameterStorageClass enum?

reply Andrej Mitrovic <none none.none> writes:
import std.stdio;
import std.traits;

alias ParameterStorageClassTuple STCTuple;
alias ParameterStorageClass STC;

void foo(in int[] x) { /*x[0] = 5; // This would be a compile-time error*/ }
void bar(int[] x) { x[0] = 5; }

void main()
{
    assert(STCTuple!foo[0] == STC.NONE);
    assert(STCTuple!bar[0] == STC.NONE);
}

Someone said that "in" was the default storage class when there is no storage
class specified for a parameter. But if that is true then how come bar can
modify the contents of the x parameter? If parameters really have "in" as the
default storage class, bar's function body would be a compile time error, just
like foo's is if you uncomment its code. (Yes, I know a fat pointer is passed
in with both functions. But "in" is supposed to give some guarantees as to what
you can do with a parameter.)

So, which part of this am I misunderstanding here?
Jan 20 2011
next sibling parent Jonathan M Davis <jmdavisProg gmx.com> writes:
On Thursday, January 20, 2011 19:03:09 Andrej Mitrovic wrote:
 import std.stdio;
 import std.traits;
 
 alias ParameterStorageClassTuple STCTuple;
 alias ParameterStorageClass STC;
 
 void foo(in int[] x) { /*x[0] = 5; // This would be a compile-time error*/
 } void bar(int[] x) { x[0] = 5; }
 
 void main()
 {
     assert(STCTuple!foo[0] == STC.NONE);
     assert(STCTuple!bar[0] == STC.NONE);
 }
 
 Someone said that "in" was the default storage class when there is no
 storage class specified for a parameter. But if that is true then how come
 bar can modify the contents of the x parameter? If parameters really have
 "in" as the default storage class, bar's function body would be a compile
 time error, just like foo's is if you uncomment its code. (Yes, I know a
 fat pointer is passed in with both functions. But "in" is supposed to give
 some guarantees as to what you can do with a parameter.)
 
 So, which part of this am I misunderstanding here?
Umm. in is never the default. in is essentially an alias for const scope. The default is non-shared and mutable. - Jonathan M Davis
Jan 20 2011
prev sibling parent reply Andrej Mitrovic <andrej.mitrovich gmail.com> writes:
On 1/21/11, Jonathan M Davis <jmdavisProg gmx.com> wrote:
 Umm. in is never the default. in is essentially an alias for const scope.
 The
 default is non-shared and mutable.

 - Jonathan M Davis
That's what I thought. But I did saw it mentioned in this NG a couple of times, I can't remember by who though. In any case, "in" seems to be missing from that enum definition. So unless there's a specific reason for its absence, I'd file an enhancement request.
Jan 20 2011
next sibling parent Lutger Blijdestijn <lutger.blijdestijn gmail.com> writes:
Andrej Mitrovic wrote:

 On 1/21/11, Jonathan M Davis <jmdavisProg gmx.com> wrote:
 Umm. in is never the default. in is essentially an alias for const scope.
 The
 default is non-shared and mutable.

 - Jonathan M Davis
That's what I thought. But I did saw it mentioned in this NG a couple of times, I can't remember by who though. In any case, "in" seems to be missing from that enum definition. So unless there's a specific reason for its absence, I'd file an enhancement request.
It's not needed because it should resolve to SCOPE for ParameterStorageClass and const is not a storage class, but a type constructor.
Jan 20 2011
prev sibling parent Christopher Nicholson-Sauls <ibisbasenji gmail.com> writes:
On 01/20/11 21:57, Andrej Mitrovic wrote:
 On 1/21/11, Jonathan M Davis <jmdavisProg gmx.com> wrote:
 Umm. in is never the default. in is essentially an alias for const scope.
 The
 default is non-shared and mutable.

 - Jonathan M Davis
That's what I thought. But I did saw it mentioned in this NG a couple of times, I can't remember by who though. In any case, "in" seems to be missing from that enum definition. So unless there's a specific reason for its absence, I'd file an enhancement request.
It's possible someone was talking about D1 where 'in' meant something very different, and was in fact the default. -- Chris N-S
Jan 22 2011