• "Dan" <dbdavidson yahoo.com> Nov 21 2012
• Philippe Sigaud <philippe.sigaud gmail.com> Nov 21 2012

"Dan" <dbdavidson yahoo.com> writes:

If I have a type tuple TL, which happens to be:
   alias TypeTuple!(const(int), immutable(double), string) TL;

How can I convert it into a tuple of (int, double, string)?

Effectively I need a way to get a new UnqualTL where each type in 
the list is itself unqualified. I need to do this without knowing 
the alias.

Thanks
Dan

Philippe Sigaud <philippe.sigaud gmail.com> writes:

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You can use std.typetuple.staticMap to map Unqual on each type:


import std.typetuple;
import std.stdio;

template UnqualifyTuple(T...)
{
    alias staticMap!(Unqual, T) UnqualifyTuple;
}

void main()
{
    alias TypeTuple!(const(int), immutable(double), string) TL;
    writeln(TL.stringof);

    alias UnqualifyTuple!TL UQTL;
    writeln(UQTL.stringof);
}

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You can use std.typetuple.staticMap to map Unqual on each type:<div><br></d=
iv><div><br></div><div>import std.typetuple;</div><div>import std.stdio;</d=
iv><div><br></div><div><div>template UnqualifyTuple(T...)</div><div>{</div>
<div>=C2=A0 =C2=A0 alias staticMap!(Unqual, T) UnqualifyTuple;</div><div>}<=
/div><div><br></div><div>void main()</div><div>{</div><div>=C2=A0 =C2=A0 al=
ias TypeTuple!(const(int), immutable(double), string) TL;</div><div>=C2=A0 =
=C2=A0 writeln(TL.stringof);</div>
<div><br></div><div>=C2=A0 =C2=A0 alias UnqualifyTuple!TL UQTL;</div><div>=
=C2=A0 =C2=A0 writeln(UQTL.stringof);</div><div>}</div></div>

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