digitalmars.D.learn - std.range lockstep is not input range but opApply entity. Workarounds?
- mist (6/6) Dec 29 2012 I basically want to be able to do stuff like this:
- Simen Kjaeraas (16/22) Dec 29 2012 Use std.range.zip instead:
- mist (5/31) Dec 29 2012 Any objections to documentation update to cross-reference zip and
- =?UTF-8?B?QWxpIMOHZWhyZWxp?= (13/19) Dec 29 2012 Tuples have already been integrated at least as much: :)
- mist (4/26) Dec 29 2012 Not clever enough to expand like this though:
- Simen Kjaeraas (6/9) Dec 29 2012 That oughta be doable. However, seeing as std.functional only contains
I basically want to be able to do stuff like this: auto result = map!( (a, b) => a+b )( lockstep(range1, range2) ); Are there any standard short ways to wrap an input range around struct with opApply (which Lockstep is)? Also what about redesigning Lockstep as a proper range? I could do a pull request but not sure about current intentions.
Dec 29 2012
On 2012-48-29 14:12, mist <none none.none> wrote:I basically want to be able to do stuff like this: auto result = map!( (a, b) => a+b )( lockstep(range1, range2) ); Are there any standard short ways to wrap an input range around struct with opApply (which Lockstep is)? Also what about redesigning Lockstep as a proper range? I could do a pull request but not sure about current intentions.Use std.range.zip instead: auto result = map!( (a, b) => a+b )( zip(range1, range2) ); The reason there are two ways is lockstep works better with foreach: foreach (a, b; lockstep(A, B) ) { // Use a and b here. } Contrast with zip: foreach (a; zip(A, B) ) { // Use a[0] and a[1] here. } There have been suggestions to better integrate tuples in the language, so in the future zip may have all the advantages of lockstep (and vice versa), but don't cross your fingers. -- Simen
Dec 29 2012
Any objections to documentation update to cross-reference zip and lockstep to each other? Was not even searching for first one when found lockstep, huh. On Saturday, 29 December 2012 at 14:19:39 UTC, Simen Kjaeraas wrote:On 2012-48-29 14:12, mist <none none.none> wrote:I basically want to be able to do stuff like this: auto result = map!( (a, b) => a+b )( lockstep(range1, range2) ); Are there any standard short ways to wrap an input range around struct with opApply (which Lockstep is)? Also what about redesigning Lockstep as a proper range? I could do a pull request but not sure about current intentions.Use std.range.zip instead: auto result = map!( (a, b) => a+b )( zip(range1, range2) ); The reason there are two ways is lockstep works better with foreach: foreach (a, b; lockstep(A, B) ) { // Use a and b here. } Contrast with zip: foreach (a; zip(A, B) ) { // Use a[0] and a[1] here. } There have been suggestions to better integrate tuples in the language, so in the future zip may have all the advantages of lockstep (and vice versa), but don't cross your fingers.
Dec 29 2012
On 12/29/2012 06:19 AM, Simen Kjaeraas wrote:foreach (a; zip(A, B) ) { // Use a[0] and a[1] here. } There have been suggestions to better integrate tuples in the language, so in the future zip may have all the advantages of lockstep (and vice versa), but don't cross your fingers.Tuples have already been integrated at least as much: :) import std.stdio; import std.range; void main() { int[] cats; int[] birds; foreach (cat, bird; zip(cats, birds)) { writeln(cat, bird); } } Ali
Dec 29 2012
Not clever enough to expand like this though: map!( (a, b) => a+b )( zip(Range1, Range2) ); Using a => a[0]+a[1] is not that big deal though. On Saturday, 29 December 2012 at 17:58:55 UTC, Ali Çehreli wrote:On 12/29/2012 06:19 AM, Simen Kjaeraas wrote:foreach (a; zip(A, B) ) { // Use a[0] and a[1] here. } There have been suggestions to better integrate tuples in thelanguage,so in the future zip may have all the advantages of lockstep(and viceversa), but don't cross your fingers.Tuples have already been integrated at least as much: :) import std.stdio; import std.range; void main() { int[] cats; int[] birds; foreach (cat, bird; zip(cats, birds)) { writeln(cat, bird); } } Ali
Dec 29 2012
On 2012-52-29 20:12, mist <none none.none> wrote:Not clever enough to expand like this though: map!( (a, b) => a+b )( zip(Range1, Range2) ); Using a => a[0]+a[1] is not that big deal though.That oughta be doable. However, seeing as std.functional only contains unaryFun and binaryFun (dranges has naryFun), this approach cannot currently extend to tuples with more than two fields. -- Simen
Dec 29 2012