digitalmars.D.learn - how to compare the type of a subclass
- Eric (12/12) Nov 21 2014 Suppose I have:
- anonymous (2/14) Nov 21 2014 assert(typeid(x) == typeid(Y));
- Eric (4/25) Nov 21 2014 Thanks. That works. I have't quite mastered the whole
- H. S. Teoh via Digitalmars-d-learn (33/44) Nov 21 2014 Binary `is` (i.e., `a is b`) is for comparing two references for
- Eric (4/65) Nov 21 2014 Thanks, this helps a lot.
- anonymous (17/27) Nov 21 2014 [...]
Suppose I have: module test; class X { } class Y : X { } Y y = new Y; X x = y; assert(is(typeof(x) == test.Y); // this assertion will fail assert(typeid(x).toString() == "test.Y"); // this assertion will pass Is there a way I can check the type of x without doing a string comparison? -Eric
Nov 21 2014
On Friday, 21 November 2014 at 22:15:37 UTC, Eric wrote:Suppose I have: module test; class X { } class Y : X { } Y y = new Y; X x = y; assert(is(typeof(x) == test.Y); // this assertion will fail assert(typeid(x).toString() == "test.Y"); // this assertion will pass Is there a way I can check the type of x without doing a string comparison? -Ericassert(typeid(x) == typeid(Y));
Nov 21 2014
On Friday, 21 November 2014 at 22:25:32 UTC, anonymous wrote:On Friday, 21 November 2014 at 22:15:37 UTC, Eric wrote:Thanks. That works. I have't quite mastered the whole is/typeof/typeid thing yet.Suppose I have: module test; class X { } class Y : X { } Y y = new Y; X x = y; assert(is(typeof(x) == test.Y); // this assertion will fail assert(typeid(x).toString() == "test.Y"); // this assertion will pass Is there a way I can check the type of x without doing a string comparison? -Ericassert(typeid(x) == typeid(Y));
Nov 21 2014
On Fri, Nov 21, 2014 at 10:30:51PM +0000, Eric via Digitalmars-d-learn wrote:On Friday, 21 November 2014 at 22:25:32 UTC, anonymous wrote:[...]On Friday, 21 November 2014 at 22:15:37 UTC, Eric wrote:Binary `is` (i.e., `a is b`) is for comparing two references for equality. It returns true if two class reference point to the same object; false otherwise. But you probably already know this. Unary `is` (`is(...)`) is a monstrous maze of obscure syntax, that's best learned on a case-by-case basis. :-) But in this particular case, it's basically to provide a context for comparing types, since types aren't actual objects at runtime. So you can't write `if (typeof(a) == typeof(b))`, for example, because types aren't objects. Instead, you have to write `if (is(typeof(a) == typeof(b)))`. `typeof` is to extract types at compile-time. It returns the *declared* type of the variable (which may not be the most derived class if you assigned a derived object to a base class reference). `typeid` is to introspect types at runtime. It returns the most derived type of the object, even if the declared type is a base class. The returned type is an actual runtime object -- since at compile-time, the most derived type may not be known, so it's not representable as an actual type at compile-time. Instead, the D runtime returns a TypeInfo object that corresponds with the runtime type of the object. So you don't need to (and shouldn't) use `is(...)` when comparing typeid's. In short: To compare (declared) types at compile time: is(typeof(x) == typeof(y)) // x has the same (declared) type as y is(typeof(x) : typeof(y)) // x implicitly converts to y To compare (actual) types at runtime: typeid(x) == typeid(y) // x has the same (actual) time as y cast(B)x !is null // x is a derived class instance of base class B There are many other cases, of course, but these are the pertinent ones in the context of your original question. T -- Never wrestle a pig. You both get covered in mud, and the pig likes it.Thanks. That works. I have't quite mastered the whole is/typeof/typeid thing yet.Is there a way I can check the type of x without doing a string comparison? -Ericassert(typeid(x) == typeid(Y));
Nov 21 2014
On Friday, 21 November 2014 at 22:52:54 UTC, H. S. Teoh via Digitalmars-d-learn wrote:On Fri, Nov 21, 2014 at 10:30:51PM +0000, Eric via Digitalmars-d-learn wrote:Thanks, this helps a lot. -EricOn Friday, 21 November 2014 at 22:25:32 UTC, anonymous wrote:[...]On Friday, 21 November 2014 at 22:15:37 UTC, Eric wrote:Binary `is` (i.e., `a is b`) is for comparing two references for equality. It returns true if two class reference point to the same object; false otherwise. But you probably already know this. Unary `is` (`is(...)`) is a monstrous maze of obscure syntax, that's best learned on a case-by-case basis. :-) But in this particular case, it's basically to provide a context for comparing types, since types aren't actual objects at runtime. So you can't write `if (typeof(a) == typeof(b))`, for example, because types aren't objects. Instead, you have to write `if (is(typeof(a) == typeof(b)))`. `typeof` is to extract types at compile-time. It returns the *declared* type of the variable (which may not be the most derived class if you assigned a derived object to a base class reference). `typeid` is to introspect types at runtime. It returns the most derived type of the object, even if the declared type is a base class. The returned type is an actual runtime object -- since at compile-time, the most derived type may not be known, so it's not representable as an actual type at compile-time. Instead, the D runtime returns a TypeInfo object that corresponds with the runtime type of the object. So you don't need to (and shouldn't) use `is(...)` when comparing typeid's. In short: To compare (declared) types at compile time: is(typeof(x) == typeof(y)) // x has the same (declared) type as y is(typeof(x) : typeof(y)) // x implicitly converts to y To compare (actual) types at runtime: typeid(x) == typeid(y) // x has the same (actual) time as y cast(B)x !is null // x is a derived class instance of base class B There are many other cases, of course, but these are the pertinent ones in the context of your original question. TThanks. That works. I have't quite mastered the whole is/typeof/typeid thing yet.Is there a way I can check the type of x without doing a string comparison? -Ericassert(typeid(x) == typeid(Y));
Nov 21 2014
On Friday, 21 November 2014 at 22:30:52 UTC, Eric wrote:On Friday, 21 November 2014 at 22:25:32 UTC, anonymous wrote:[...]On Friday, 21 November 2014 at 22:15:37 UTC, Eric wrote:[...]class X { } class Y : X { } Y y = new Y; X x = y;I have't quite mastered the whole is/typeof/typeid thing yet.Maybe this helps: There are two worlds: * the static world = the compile time world = the world of types and constant values, * the dynamic = the run time world = the world of values. Obviously, there are no variable values in the static world. Maybe less obviously, there are no types in the dynamic world. The variable x is statically typed as X. is(...) and typeof(...) operate on this level. But the object stored in x is being constructed as a Y at run time. That information is available through typeid. typeid(...) is not a type, it's a value of type TypeInfo which corresponds to a type. typeid(Y) and typeid(x) are TypeInfo objects both corresponding to the type Y.
Nov 21 2014