• d coder <dlang.coder gmail.com> Mar 11 2011
• "Steven Schveighoffer" <schveiguy yahoo.com> Mar 11 2011

d coder <dlang.coder gmail.com> writes:

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Greetings

Please look at the code down here. When compiled and run, I get the message
"Call to postblit" printed. I think it is because of the foreach block,
because the variable "i" is not declared as ref there. Is there a way to
make it a ref?

Regards
- Puneet

import std.stdio;

struct Foo {
  this(this) {
    writeln("Call to postblit");
  }
}

class Bar {
  Foo foo;
  this() {
    foreach(i, f; this.tupleof) {
      // do nothing
    }
  }
}

void main()
{
  Bar bar = new Bar();
}

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<div>Greetings</div><div><br></div><div>Please look at the code down here. =
When compiled and run, I get the message &quot;Call to postblit&quot; print=
ed. I think it is because of the foreach block, because the variable &quot;=
i&quot; is not declared as ref there. Is there a way to make it a ref?</div=


<div><br></div><div>Regards</div><div>- Puneet</div><div><br></div><div>imp=
ort std.stdio;</div><div><br></div><div>struct Foo {</div><div>=A0 this(thi=
s) {</div><div>=A0 =A0 writeln(&quot;Call to postblit&quot;);</div><div>=A0=
 }</div>

<div>}</div><div><br></div><div>class Bar {</div><div>=A0 Foo foo;</div><di=
v>=A0 this() {</div><div>=A0 =A0 foreach(i, f; this.tupleof) {</div><div>=
=A0 =A0 =A0 // do nothing</div><div>=A0 =A0 }</div><div>=A0 }</div><div>}</=
div><div><br></div>

<div>void main()</div><div>{</div><div>=A0 Bar bar =3D new Bar();</div><div=
}</div><div><br></div>


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"Steven Schveighoffer" <schveiguy yahoo.com> writes:

On Fri, 11 Mar 2011 04:50:38 -0500, d coder <dlang.coder gmail.com> wrote:

 Greetings

 Please look at the code down here. When compiled and run, I get the  
 message
 "Call to postblit" printed. I think it is because of the foreach block,
 because the variable "i" is not declared as ref there. Is there a way to
 make it a ref?

 Regards
 - Puneet

 import std.stdio;

 struct Foo {
   this(this) {
     writeln("Call to postblit");
   }
 }

 class Bar {
   Foo foo;
   this() {
     foreach(i, f; this.tupleof) {
       // do nothing
     }
   }
 }

 void main()
 {
   Bar bar = new Bar();
 }


This typically works in a foreach loop:

foreach(i, ref f; x)

but a foreach for a tuple is a special beast, and using ref in your code  
yields this error:

foreachtuple.d(12): Error: no storage class for value f

But I agree it should be doable.  This should qualify for an enhancement  
request: http://d.puremagic.com/issues/enter_bug.cgi?product=D

-Steve