• Rory Mcguire (10/10) Aug 19 2010 Are all string literals that have the same value initialized to the same...
• Jonathan Davis (6/16) Aug 19 2010 Well, since in Windows at least, string literals can be concatenated
• Stewart Gordon (9/12) Aug 19 2010 I can't see how testing each string literal to see if it's the same
• bearophile (4/8) Aug 19 2010 Probably a conforming D implementation is free to not give the same addr...
• Johannes Pfau (10/23) Aug 19 2010 I don't think so. It might work now, as we only have static linking, but
• Simen kjaeraas (8/18) Aug 19 2010 No. The same string in different object files may be different instances...
• Sean Kelly (2/15) Aug 19 2010 This should be expected but I wouldn't rely upon it.
• Rory Mcguire (5/18) Aug 20 2010 Interesting thanks guys.

Rory Mcguire <rjmcguire gm_no_ail.com> writes:

Are all string literals that have the same value initialized to the same 
address?

void main() {
	string same() {
		return "This";
	}
	assert("This" is same());
	assert("This" is "This");
}


Can this be relied upon?

Jonathan Davis <jmdavisprog gmail.com> writes:

On 8/19/10, Rory Mcguire <rjmcguire gm_no_ail.com> wrote:
 Are all string literals that have the same value initialized to the same
 address?

 void main() {
 	string same() {
 		return "This";
 	}
 	assert("This" is same());
 	assert("This" is "This");
 }


 Can this be relied upon?

Well, since in Windows at least, string literals can be concatenated
to and whatnot, I very much doubt that there's any sharing involved.
You can always check with the is operator though. If it reports true,
then the two strings have the same instance. If it reports false, then
they don't.

Stewart Gordon <smjg_1998 yahoo.com> writes:

Jonathan Davis wrote:
<snip>
 You can always check with the is operator though. If it reports true,
 then the two strings have the same instance. If it reports false, then
 they don't.

I can't see how testing each string literal to see if it's the same 
instance as another can work.

The OP's point is: Are identical string literals *guaranteed* to be the 
same instance?  Regardless of implementation?  Regardless of whether 
they're next to each other, in different modules or anything in between? 
  Regardless of the phase of the moon?

Stewart.

bearophile <bearophileHUGS lycos.com> writes:

Rory Mcguire:

 Are all string literals that have the same value initialized to the same 
 address?
 ...
 Can this be relied upon?

Probably a conforming D implementation is free to not give the same address to
those.

Bye,
bearophile

Johannes Pfau <spam example.com> writes:

On 19.08.2010 09:53, Rory Mcguire wrote:
 Are all string literals that have the same value initialized to the same 
 address?
 
 void main() {
 	string same() {
 		return "This";
 	}
 	assert("This" is same());
 	assert("This" is "This");
 }
 
 
 Can this be relied upon?

I don't think so. It might work now, as we only have static linking, but
what happens if we have 2 independent shared libraries with the string
"This"? Each library has to include the string because the libraries
don't depend on each other, but as soon as a program uses both libraries
there are 2 memory locations where the string could be. (I guess the
linker won't do some magic to make these point at the same location. But
I might be wrong.)

-- 
Johannes Pfau

"Simen kjaeraas" <simen.kjaras gmail.com> writes:

Rory Mcguire <rjmcguire gm_no_ail.com> wrote:

 Are all string literals that have the same value initialized to the same
 address?

 void main() {
 	string same() {
 		return "This";
 	}
 	assert("This" is same());
 	assert("This" is "This");
 }


 Can this be relied upon?

No. The same string in different object files may be different instances,
as may of course those in dynamically linked libraries. I would think the
optimizer feels free to move string literals around as it sees fit, and
the spec does not anywhere state that the compiler should merge string
literals.

-- 
Simen

Sean Kelly <sean invisibleduck.org> writes:

Rory Mcguire Wrote:

 Are all string literals that have the same value initialized to the same 
 address?
 
 void main() {
 	string same() {
 		return "This";
 	}
 	assert("This" is same());
 	assert("This" is "This");
 }
 
 
 Can this be relied upon?

This should be expected but I wouldn't rely upon it.

Rory Mcguire <rjmcguire gm_no_ail.com> writes:

Rory Mcguire wrote:

 Are all string literals that have the same value initialized to the same
 address?
 
 void main() {
 string same() {
 return "This";
 }
 assert("This" is same());
 assert("This" is "This");
 }
 
 
 Can this be relied upon?


Interesting thanks guys.

Was just curious about the speed of comparisons for string literals. Because
I believe the string comparisons check if a string "is" another string 
first.