digitalmars.D.learn - Q: How to return sub class from base class method

Myron Alexander (9/33) Jun 17 2007 The method chain fails as doSomething returns type A.

Jari-Matti =?ISO-8859-1?Q?M=E4kel=E4?= (17/44) Jun 17 2007 Yes, you can use CRTP

Myron Alexander (8/28) Jun 17 2007 Thanks for the suggestion. I am hoping for a solution that does not
Kirk McDonald (16/68) Jun 17 2007 I believe B should look like this, if you're using that pattern:

Jari-Matti =?ISO-8859-1?Q?M=E4kel=E4?= (10/41) Jun 17 2007 Actually no - class B was supposed to be in the middle of the hierarchy ...

Myron Alexander (9/55) Jun 18 2007 Thanks all.

Myron Alexander <someone somewhere.com> writes:

Hello.

I have a class structure as such:

 class A {
    typeof(this) doSomething (????) {
       ...
       return this;
    }
 }
 
 class B : A {
    typeof(this) doSomethingElse (????) {
       ...
       return this;
    }
 }
 
 void main () {
    // Fails
    B b = (new B()).doSomething (???).doSomethingElse (???);
 }

The method chain fails as doSomething returns type A.

I want to define method doSomething in such a way that it will return 
the specialized type (B) rather than the base type.

I'm currently using a mixin to mixin overriding code:

 template doSomethingOverride () {
    override typeof(this) doSomething (????) {
       super.doSomething (????);
       return this;
    }
 }

Is there a way to set the return type as the type instantiated?

Thanks,

Myron.

Jun 17 2007

Jari-Matti =?ISO-8859-1?Q?M=E4kel=E4?= <jmjmak utu.fi.invalid> writes:

Myron Alexander wrote:

 I have a class structure as such:
 
 class A {
    typeof(this) doSomething (????) {
       ...
       return this;
    }
 }
 
 class B : A {
    typeof(this) doSomethingElse (????) {
       ...
       return this;
    }
 }
 
 void main () {
    // Fails
    B b = (new B()).doSomething (???).doSomethingElse (???);
 }

 
 The method chain fails as doSomething returns type A.
 
 I want to define method doSomething in such a way that it will return
 the specialized type (B) rather than the base type.
 
 Is there a way to set the return type as the type instantiated?

Yes, you can use CRTP
(http://en.wikipedia.org/wiki/Curiously_Recurring_Template_Pattern).

class A(T) {
  T doSomething() {
    ...
    return cast(T)this;
  }
}

class B(T) : A!(T) {
  T doSomethingElse() {
    ...
    return cast(T)this;
  }
}

There might be other (more clever) ways to do this too. Like a mixin for
the "selftype" or something.

Jun 17 2007

Myron Alexander <someone somewhere.com> writes:

Jari-Matti M�kel� wrote:
 
 Yes, you can use CRTP
 (http://en.wikipedia.org/wiki/Curiously_Recurring_Template_Pattern).
 
 class A(T) {
   T doSomething() {
     ...
     return cast(T)this;
   }
 }
 
 class B(T) : A!(T) {
   T doSomethingElse() {
     ...
     return cast(T)this;
   }
 }
 
 There might be other (more clever) ways to do this too. Like a mixin for
 the "selftype" or something.

Thanks for the suggestion. I am hoping for a solution that does not 
require me to set a type on instantiation. I just want to write:

B b = (new B()).doSomething (???).doSomethingElse (???);

If the language does not have a way to do it, that's ok, the mixin 
solution works.

Regards,

Myron.

Jun 17 2007

Kirk McDonald <kirklin.mcdonald gmail.com> writes:

Jari-Matti M�kel� wrote:
 Myron Alexander wrote:
 
 
I have a class structure as such:


class A {
   typeof(this) doSomething (????) {
      ...
      return this;
   }
}

class B : A {
   typeof(this) doSomethingElse (????) {
      ...
      return this;
   }
}

void main () {
   // Fails
   B b = (new B()).doSomething (???).doSomethingElse (???);
}

The method chain fails as doSomething returns type A.

I want to define method doSomething in such a way that it will return
the specialized type (B) rather than the base type.

Is there a way to set the return type as the type instantiated?

 
 
 Yes, you can use CRTP
 (http://en.wikipedia.org/wiki/Curiously_Recurring_Template_Pattern).
 
 class A(T) {
   T doSomething() {
     ...
     return cast(T)this;
   }
 }
 
 class B(T) : A!(T) {
   T doSomethingElse() {
     ...
     return cast(T)this;
   }
 }
 
 There might be other (more clever) ways to do this too. Like a mixin for
 the "selftype" or something.

I believe B should look like this, if you're using that pattern:

class B : A!(B) {
   B doSomethingElse() {
     // ...
     return this;
   }
}

Thus, B is derived from a class template to which you pass B as a 
parameter. This is often used in C++ as a way of emulating mixin-like 
behavior. Thus, D's template mixins could very well be a better solution.

-- 
Kirk McDonald
http://kirkmcdonald.blogspot.com
Pyd: Connecting D and Python
http://pyd.dsource.org

Jun 17 2007

Jari-Matti =?ISO-8859-1?Q?M=E4kel=E4?= <jmjmak utu.fi.invalid> writes:

Kirk McDonald wrote:

 Jari-Matti M�kel� wrote:
 class A(T) {
   T doSomething() {
     ...
     return cast(T)this;
   }
 }
 
 class B(T) : A!(T) {
   T doSomethingElse() {
     ...
     return cast(T)this;
   }
 }
 
 There might be other (more clever) ways to do this too. Like a mixin for
 the "selftype" or something.

 
 I believe B should look like this, if you're using that pattern:
 
 class B : A!(B) {
    B doSomethingElse() {
      // ...
      return this;
    }
 }

Actually no - class B was supposed to be in the middle of the hierarchy so
class C would have looked like that :)

Something like

class A(T = A) { ... }
class B(T = B) : A!(T) { ... }

would have been nice for those non-abstract base classes so they could have
been instantiated too, but apparently the compiler didn't want to
co-operate this time.

 
 Thus, B is derived from a class template to which you pass B as a
 parameter. This is often used in C++ as a way of emulating mixin-like
 behavior. Thus, D's template mixins could very well be a better solution.
 

Feel free to create a better solution :)

Jun 17 2007

Myron Alexander <someone somewhere.com> writes:

Jari-Matti M�kel� wrote:
 Kirk McDonald wrote:
 
 Jari-Matti M�kel� wrote:
 class A(T) {
   T doSomething() {
     ...
     return cast(T)this;
   }
 }

 class B(T) : A!(T) {
   T doSomethingElse() {
     ...
     return cast(T)this;
   }
 }

 There might be other (more clever) ways to do this too. Like a mixin for
 the "selftype" or something.

 I believe B should look like this, if you're using that pattern:

 class B : A!(B) {
    B doSomethingElse() {
      // ...
      return this;
    }
 }

 
 Actually no - class B was supposed to be in the middle of the hierarchy so
 class C would have looked like that :)
 
 Something like
 
 class A(T = A) { ... }
 class B(T = B) : A!(T) { ... }
 
 would have been nice for those non-abstract base classes so they could have
 been instantiated too, but apparently the compiler didn't want to
 co-operate this time.
 
 Thus, B is derived from a class template to which you pass B as a
 parameter. This is often used in C++ as a way of emulating mixin-like
 behavior. Thus, D's template mixins could very well be a better solution.

 
 Feel free to create a better solution :)

Thanks all.

I am happy with the mixin solution, even if I forget to add the mixin, 
the compiler will generate an error when I try to chain the class 
methods after the doSomething so it's not a dangerous one at that.

Just for your information, I attached the test source where I am using 
it. The doSomething method here is called 'initCause'.

Regards,

Myron.

Jun 18 2007

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digitalmars.D.learn - Q: How to return sub class from base class method