• %u (7/7) Jul 22 2010 How to parse a simple format with ranges? For example a query string for...
• =?iso-8859-2?B?VG9tZWsgU293afFza2k=?= (17/25) Jul 23 2010 Something like this (not tested):

%u <e sp.am> writes:

How to parse a simple format with ranges? For example a query string format:

string[string] params = parse("foo=1&bar=1%202&baz=1+2+3");
assert(params["foo"] == "1");
assert(params["bar"] == "1 2");
assert(params["baz"] == "1 2 3");

parse() should accept a string, an stream or anything else that make sense.

Thanks

=?iso-8859-2?B?VG9tZWsgU293afFza2k=?= <just ask.me> writes:

Dnia 22-07-2010 o 15:22:14 %u <e sp.am> napisa=B3(a):

 How to parse a simple format with ranges? For example a query string  =

 format:

 string[string] params =3D parse("foo=3D1&bar=3D1%202&baz=3D1+2+3");
 assert(params["foo"] =3D=3D "1");
 assert(params["bar"] =3D=3D "1 2");
 assert(params["baz"] =3D=3D "1 2 3");

 parse() should accept a string, an stream or anything else that make  =

 sense.

Something like this (not tested):

import std.algorithm;

string[string] parse(R)(R input) {
string[string] params;
foreach (assignment; splitter(input, '&')) {
     auto a =3D splitter(assignment, '=3D');
     string lvalue =3D a.front;
     a.popFront;
     string rvalue =3D replace(a.front, '+', ' ');
     params[lvalue] =3D rvalue;
     a.popFront;
     assert (a.empty);
}
return params;
}

Tomek