• Enjoys Math (4/4) Feb 05 2016 SDL_RenderCopy(...) takes two pointers to SDL_Rect's,
• =?UTF-8?Q?Ali_=c3=87ehreli?= (21/26) Feb 05 2016 Does it compile and produce an incorrect result? For it to compile, the
• Enjoys Math (2/7) Feb 05 2016 Got it. I was taking the address of a return-by-copy property.

Enjoys Math <enjoysmath gmail.com> writes:

SDL_RenderCopy(...) takes two pointers to SDL_Rect's,

I have a property method in another class returning the SDL_Rect 
equivalent of a Box (my structure).  Taking ampersand on the left 
of a call to the property does not give the address (&).

=?UTF-8?Q?Ali_=c3=87ehreli?= <acehreli yahoo.com> writes:

On 02/05/2016 03:53 PM, Enjoys Math wrote:
 SDL_RenderCopy(...) takes two pointers to SDL_Rect's,

 I have a property method in another class returning the SDL_Rect
 equivalent of a Box (my structure).

Returning by reference or by value?

 Taking ampersand on the left of a
 call to the property does not give the address (&).

Does it compile and produce an incorrect result? For it to compile, the 
returned object must be an lvalue. The following works (not the 
commented-out part):

import std.stdio;

struct S {
}

S s;

S returnsCopy() {
     return s;
}

ref S returnsRef() {
     return s;
}

void main() {
     // auto addr = &returnsCopy();
     auto addr = &returnsRef();
     writeln(addr);
}

Ali

Enjoys Math <enjoysmath gmail.com> writes:

On Friday, 5 February 2016 at 23:53:15 UTC, Enjoys Math wrote:
 SDL_RenderCopy(...) takes two pointers to SDL_Rect's,

 I have a property method in another class returning the 
 SDL_Rect equivalent of a Box (my structure).  Taking ampersand 
 on the left of a call to the property does not give the address 
 (&).

Got it.  I was taking the address of a return-by-copy property.