• Ben (15/15) Nov 02 2015 When I create a generator using an interface (or abstract class)

Ben <bencschulz gmail.com> writes:

When I create a generator using an interface (or abstract class) 
I must cast the concrete instance to the interface. Why does the 
Generator not know that B is a implementation of the interface of 
A?

/// Test Code
interface A {}
class B : A{}

// Fails
auto testGen1 = new Generator!A({
     yield (new B());
});

// Succeeds
auto testGen2 = new Generator!A({
     yield ( cast(A) new B());
});