• "js.mdnq" <js_adddot+mdng gmail.com> Dec 04 2012
• "Adam D. Ruppe" <destructionator gmail.com> Dec 04 2012
• "Adam D. Ruppe" <destructionator gmail.com> Dec 04 2012

"js.mdnq" <js_adddot+mdng gmail.com> writes:

I have a class

static class myclass(T)
{
    static void myfunc();
}

which I have to call like myclass!Q.myfunc();

How can I create a default type so that I can call it like 
myclass.myfunc()?

I've tried

static class myclass(T = int) and (alias T = int), neither worked.

"Adam D. Ruppe" <destructionator gmail.com> writes:

 How can I create a default type so that I can call it like 
 myclass.myfunc()?


Can't do that. Best you can do is myclass!().myfunc, then it will 
use the default type (write it is (T = int) bw) but you have to 
put in the !() to actually use the template.

There's a patch for the compiler to change this, but the compiler 
devs are split on if it is actually a good idea or not, because 
of a few cases, one I remember is:

template foo(T = int) {}

alias foo bar; // is bar == foo or is bar == foo!int ?

bar!float; // legal or illegal? It is legal today, but with the 
patch it becomes questionable

"Adam D. Ruppe" <destructionator gmail.com> writes:

BTW you can do:

class myclass_custom(T = int) {}

alias myclass_custom!int myclass;


Then use myclass.whatever and you get int. If you want a custom 
type then, you'd use the other name (myclass_custom!ubyte for 
instance)