digitalmars.D.learn - D 2.x invariant question
- Charles D Hixson <charleshixsn earthlink.net> Oct 31 2007
- "Jarrett Billingsley" <kb3ctd2 yahoo.com> Oct 31 2007
- Charles D Hixson <charleshixsn earthlink.net> Oct 31 2007
Would the following function:
invariant Body opIndex (Key k)
{ if (k in _cache)
{ ....
return _cache[k].bdy;
}
return null;
}
return values that were invariant, or would that type have to
be declared at the declaration of the type "Body"?
Oct 31 2007
"Charles D Hixson" <charleshixsn earthlink.net> wrote in message news:fgao71$21fp$1 digitalmars.com...Would the following function: invariant Body opIndex (Key k) { if (k in _cache) { .... return _cache[k].bdy; } return null; } return values that were invariant, or would that type have to be declared at the declaration of the type "Body"?
I think this makes the method opIndex invariant, which means this function can only access invariant members, or something. If you want an invariant(Body), use... invariant(Body) as the return type. Aside: performance increase, you can avoid the double lookup: if(auto val = k in cache) { ..use val here.. return val.bdy; } 'in' returns a pointer to the value, and you can declare and assign a variable in the condition of an 'if' statement.
Oct 31 2007
Jarrett Billingsley wrote:"Charles D Hixson" <charleshixsn earthlink.net> wrote in message news:fgao71$21fp$1 digitalmars.com...Would the following function: invariant Body opIndex (Key k) { if (k in _cache) { .... return _cache[k].bdy; } return null; } return values that were invariant, or would that type have to be declared at the declaration of the type "Body"?
I think this makes the method opIndex invariant, which means this function can only access invariant members, or something. If you want an invariant(Body), use... invariant(Body) as the return type. Aside: performance increase, you can avoid the double lookup: if(auto val = k in cache) { ..use val here.. return val.bdy; } 'in' returns a pointer to the value, and you can declare and assign a variable in the condition of an 'if' statement.
(I *kenw* that about "in", but I keep forgetting.)
Oct 31 2007








Charles D Hixson <charleshixsn earthlink.net>