• "Minas Mina" <minas_mina1990 hotmail.co.uk> Jul 13 2012
• Jonathan M Davis <jmdavisProg gmx.com> Jul 13 2012
• "Minas Mina" <minas_mina1990 hotmail.co.uk> Jul 14 2012
• "David Nadlinger" <see klickverbot.at> Jul 14 2012
• "Minas Mina" <minas_mina1990 hotmail.co.uk> Jul 14 2012

"Minas Mina" <minas_mina1990 hotmail.co.uk> writes:

I'm want to "play" a bit with thread syncronization...

So this is a (big) part of my code. The other is the imports, the 
thread starting and the printing of x.

shared int x;
shared Semaphore sema;

void main(string[] args)
{
	auto t1 = new Thread(&f);
	auto t2 = new Thread(&g);
	
	sema = new Semaphore(1); // error here

The error is: Error: cannot implicitly convert expression (new 
Semaphore(1u)) of type core.sync.semaphore.Semaphore to 
shared(Semaphore)

I understand what the error means, I just don't know how to fix 
it (to make it explicit). I tried new shared (Semaphore(1)) but 
doesn't work.

Jonathan M Davis <jmdavisProg gmx.com> writes:

On Saturday, July 14, 2012 01:10:46 Minas Mina wrote:
 I'm want to "play" a bit with thread syncronization...
 
 So this is a (big) part of my code. The other is the imports, the
 thread starting and the printing of x.
 
 shared int x;
 shared Semaphore sema;
 
 void main(string[] args)
 {
 	auto t1 = new Thread(&f);
 	auto t2 = new Thread(&g);
 
 	sema = new Semaphore(1); // error here
 
 The error is: Error: cannot implicitly convert expression (new
 Semaphore(1u)) of type core.sync.semaphore.Semaphore to
 shared(Semaphore)
 
 I understand what the error means, I just don't know how to fix
 it (to make it explicit). I tried new shared (Semaphore(1)) but
 doesn't work.


Try

sema = new shared(Semaphore)(1);

- Jonathan M Davis

"Minas Mina" <minas_mina1990 hotmail.co.uk> writes:

Thanks, I've got another problem:

void f()
{
	sema.wait();
	
	++x;
	
	sema.notify();
}

sema is the global shared Semaphore (as above)

main.d(29): Error: function core.sync.semaphore.Semaphore.wait () 
is not callable using argument types () shared
main.d(29): Error: expected 1 function arguments, not 0
main.d(33): Error: function core.sync.semaphore.Semaphore.notify 
() is not callable using argument types () shared

Why isn't it working as I am expecting it to? Isn't this the way 
shared is used (or should be used)?

"David Nadlinger" <see klickverbot.at> writes:

On Saturday, 14 July 2012 at 09:15:55 UTC, Minas Mina wrote:
 Isn't this the way shared is used (or should be used)?


Should be used: probably yes. But functions/methods which are 
able to act on shared data must be marked  so, and unfortunately, 
the druntime primitives are not yet annotated with shared, so you 
need to manually cast shared() away first (or just use __gshared 
instead of shared).

David

"Minas Mina" <minas_mina1990 hotmail.co.uk> writes:

On Saturday, 14 July 2012 at 09:21:27 UTC, David Nadlinger wrote:
 On Saturday, 14 July 2012 at 09:15:55 UTC, Minas Mina wrote:
 Isn't this the way shared is used (or should be used)?


 Should be used: probably yes. But functions/methods which are 
 able to act on shared data must be marked  so, and 
 unfortunately, the druntime primitives are not yet annotated 
 with shared, so you need to manually cast shared() away first 
 (or just use __gshared instead of shared).

 David


Thank you, __gshared was actually what I was looking for!