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digitalmars.D.learn - Convert this C define to D

reply Regan Heath <regan netmail.co.nz> writes:
Hi all,

I have this C macro:

#define STACK_OF(type) STACK

usage:

struct foo {
  STACK_OF(Bob) bobStack;
}

lets ignore the fact that the replacement STACK doesn't include with the type
it was given, in this case/stage it's not important.

I feel like I should be able to replace this C macro with a template/mixin of
some kind but as templates/mixins aren't my strongest d-foo (kungfoo) technique
I figured I had best ask for opinions.

Regan
May 22 2007
parent reply Daniel Keep <daniel.keep.lists gmail.com> writes:
Regan Heath wrote:

 Hi all,
 
 I have this C macro:
 
 #define STACK_OF(type) STACK
 
 usage:
 
 struct foo {
   STACK_OF(Bob) bobStack;
 }
 
 lets ignore the fact that the replacement STACK doesn't include with the type
it was given, in this case/stage it's not important.
 
 I feel like I should be able to replace this C macro with a template/mixin of
some kind but as templates/mixins aren't my strongest d-foo (kungfoo) technique
I figured I had best ask for opinions.
 
 Regan



Assuming that STACK is an actual type...

template STACK_OF(type)
{
    alias STACK STACK_OF;
}

	-- Daniel

-- 
int getRandomNumber()
{
    return 4; // chosen by fair dice roll.
              // guaranteed to be random.
}

http://xkcd.com/

v2sw5+8Yhw5ln4+5pr6OFPma8u6+7Lw4Tm6+7l6+7D
i28a2Xs3MSr2e4/6+7t4TNSMb6HTOp5en5g6RAHCP  http://hackerkey.com/
May 22 2007
parent reply Regan Heath <regan netmail.co.nz> writes:
Daniel Keep Wrote:

 Regan Heath wrote:

 Hi all,
 
 I have this C macro:
 
 #define STACK_OF(type) STACK
 
 usage:
 
 struct foo {
   STACK_OF(Bob) bobStack;
 }
 
 lets ignore the fact that the replacement STACK doesn't include with the type
it was given, in this case/stage it's not important.
 
 I feel like I should be able to replace this C macro with a template/mixin of
some kind but as templates/mixins aren't my strongest d-foo (kungfoo) technique
I figured I had best ask for opinions.
 
 Regan



 Assuming that STACK is an actual type...
 
 template STACK_OF(type)
 {
     alias STACK STACK_OF;
 }



So, using the above this:

struct foo {
  STACK_OF(Bob) bobStack;
}

results in/becomes/is equivalent to this:

struct foo {
  STACK  bobStack;
}

?

Yes, STACK is a type, a structure which has previously been defined.

Regan
May 22 2007
parent Frits van Bommel <fvbommel REMwOVExCAPSs.nl> writes:
Regan Heath wrote:

 Daniel Keep Wrote:




 Assuming that STACK is an actual type...

 template STACK_OF(type)
 {
     alias STACK STACK_OF;
 }



 So, using the above this:
 
 struct foo {
   STACK_OF(Bob) bobStack;
 }
 
 results in/becomes/is equivalent to this:
 
 struct foo {
   STACK  bobStack;
 }
 
 ?
 
 Yes, STACK is a type, a structure which has previously been defined.



Almost. You'd have to do this:
---
struct foo {
     STACK_OF!(Bob) bobStack;
}
---
Note the '!'.
May 22 2007