• simendsjo <simen.endsjo pandavre.com> Jun 25 2011
• David Nadlinger <see klickverbot.at> Jun 25 2011
• simendsjo <simen.endsjo pandavre.com> Jun 25 2011

simendsjo <simen.endsjo pandavre.com> writes:

I'm calling functions using ParameterTypeTuple. The problem arise when 
the parameters is defined as const/immutable. So I need to break out of 
the type system.
But I cannot seem to do this without using a temporary variable. Am I 
doing something wrong?

     int i = 1;
     const(int*) c;
     //c = &v; // ok - cannot modify const
     int* cp = cast(int*)c;
     cp = &v; // ok - breaking type system
     //(cast(int*)c) = &v; // cannot modify const - shouldn't this work 
as above?

David Nadlinger <see klickverbot.at> writes:

The result of a cast is not an lvalue.

David


On 6/25/11 7:37 PM, simendsjo wrote:
 I'm calling functions using ParameterTypeTuple. The problem arise when
 the parameters is defined as const/immutable. So I need to break out of
 the type system.
 But I cannot seem to do this without using a temporary variable. Am I
 doing something wrong?

 int i = 1;
 const(int*) c;
 //c = &v; // ok - cannot modify const
 int* cp = cast(int*)c;
 cp = &v; // ok - breaking type system
 //(cast(int*)c) = &v; // cannot modify const - shouldn't this work as
 above?

simendsjo <simen.endsjo pandavre.com> writes:

On 25.06.2011 19:44, David Nadlinger wrote:
 The result of a cast is not an lvalue.

 David


 On 6/25/11 7:37 PM, simendsjo wrote:
 I'm calling functions using ParameterTypeTuple. The problem arise when
 the parameters is defined as const/immutable. So I need to break out of
 the type system.
 But I cannot seem to do this without using a temporary variable. Am I
 doing something wrong?

 int i = 1;
 const(int*) c;
 //c = &v; // ok - cannot modify const
 int* cp = cast(int*)c;
 cp = &v; // ok - breaking type system
 //(cast(int*)c) = &v; // cannot modify const - shouldn't this work as
 above?




So the error message is "wrong"? The error message be something like 
"(cast(int*)c) is not an lvalue"?