digitalmars.D.learn - A function to split a range into several ranges of different chunks
- Andrej Mitrovic (24/24) Sep 14 2020 -----
- Seb (4/28) Sep 14 2020 You likely want to get involved / raise your support here:
- Andrej Mitrovic (2/4) Sep 14 2020 Oh this is great, thank you!
----- import std.range; import std.stdio; void main () { auto range = sequence!((a, n) => n); // works, but the chunks are all the same length auto rngs = range.chunks(4); writeln(rngs[0]); writeln(rngs[1]); writeln(rngs[2]); // want this auto ranges = range.???(3, 4, 5); writeln(ranges[0] == [1, 2, 3]); writeln(ranges[1] == [4, 5, 6, 7]); writeln(ranges[2] == [8, 9, 10, 11, 12]); } ----- Do you know of a simple way to do this? It's essentially similar to chunks, except the chunks themselves would not be of the same length. You can think of a good name for '???' here. Maybe this is already possible by combining functionality in std.range - but I came up short.
Sep 14 2020
On Monday, 14 September 2020 at 07:49:31 UTC, Andrej Mitrovic wrote:----- import std.range; import std.stdio; void main () { auto range = sequence!((a, n) => n); // works, but the chunks are all the same length auto rngs = range.chunks(4); writeln(rngs[0]); writeln(rngs[1]); writeln(rngs[2]); // want this auto ranges = range.???(3, 4, 5); writeln(ranges[0] == [1, 2, 3]); writeln(ranges[1] == [4, 5, 6, 7]); writeln(ranges[2] == [8, 9, 10, 11, 12]); } ----- Do you know of a simple way to do this? It's essentially similar to chunks, except the chunks themselves would not be of the same length. You can think of a good name for '???' here. Maybe this is already possible by combining functionality in std.range - but I came up short.You likely want to get involved / raise your support here: https://github.com/dlang/phobos/pull/7600
Sep 14 2020
On Monday, 14 September 2020 at 09:08:01 UTC, Seb wrote:You likely want to get involved / raise your support here: https://github.com/dlang/phobos/pull/7600Oh this is great, thank you!
Sep 14 2020