digitalmars.D.learn - ASCII code to char
- jicman <cabrera_ _wrc.xerox.com> May 26 2007
- Derek Parnell <derek psych.ward> May 26 2007
- jicman <cabrera_ _wrc.xerox.com> May 26 2007
- janderson <askme me.com> May 26 2007
Greetings! say I have an integer value representing an ASCII character, how do I get that character? I was looking through Phobos, but there was no easy way of finding it and I knew you guys could help me. thanks, josé
May 26 2007
On Sat, 26 May 2007 13:54:36 -0400, jicman wrote:Greetings! say I have an integer value representing an ASCII character, how do I get that character? I was looking through Phobos, but there was no easy way of finding it and I knew you guys could help me. thanks, josé
If the value is truely ASCII then it is any number from zero to 127 inclusive. Values outside that range are not ASCII. int val; char c; c = cast(char)val; -- Derek Parnell Melbourne, Australia "Justice for David Hicks!" skype: derek.j.parnell
May 26 2007
Derek Parnell Wrote:On Sat, 26 May 2007 13:54:36 -0400, jicman wrote:Greetings! say I have an integer value representing an ASCII character, how do I get that character? I was looking through Phobos, but there was no easy way of finding it and I knew you guys could help me. thanks, josé
If the value is truely ASCII then it is any number from zero to 127 inclusive. Values outside that range are not ASCII. int val; char c; c = cast(char)val;
Gosh... D is so easy... :-) Thanks Derek. jic
May 26 2007
jicman wrote:Derek Parnell Wrote:On Sat, 26 May 2007 13:54:36 -0400, jicman wrote:Greetings! say I have an integer value representing an ASCII character, how do I get that character? I was looking through Phobos, but there was no easy way of finding it and I knew you guys could help me. thanks, josé
inclusive. Values outside that range are not ASCII. int val; char c; c = cast(char)val;
Gosh... D is so easy... :-) Thanks Derek. jic
You should know, in C/C++ you could write: int val; char c; c = (char)val; I imagine however other languages may not be so "easy".
May 26 2007








janderson <askme me.com>