• Alexander Panek (16/16) Apr 04 2005 Hello,
• Ben Hinkle (7/18) Apr 04 2005 I haven't used the regexp module but glancing at the doc r.exec(src_buf)...
• Ben Hinkle (19/31) Apr 04 2005 I think the doc for regexp is misleading and/or incomplete. I'll add som...
• Alexander Panek (6/40) Apr 05 2005 You saved my day, thanks :).

"Alexander Panek" <alexander.panek brainsware.org> writes:

Hello,

I got a little problem with the std.regexp.RegExp.match() and .exec()  
methods. Both are just returning the first match of the pattern in the  
string..am i doing something wrong?

std.regexp.RegExp r = std.regexp.search(Source,  
"([a-zA-Z]{1,})+=\"+([a-zA-Z0-9]{1,})+\"", "i");
char[][] buf = r.match(src_buf);
while(1)
{
	Attributes ~= new Attribute(r.exec(src_buf)[0], this);
}

hoping for help =\

Regards,
Alex

-- 
huh? did you say something? :o

"Ben Hinkle" <bhinkle mathworks.com> writes:

"Alexander Panek" <alexander.panek brainsware.org> wrote in message 
news:opsopz4btty2yy8c chello080109082145.3.15.vie.surfer.at...
 Hello,

 I got a little problem with the std.regexp.RegExp.match() and .exec() 
 methods. Both are just returning the first match of the pattern in the 
 string..am i doing something wrong?

 std.regexp.RegExp r = std.regexp.search(Source, 
 "([a-zA-Z]{1,})+=\"+([a-zA-Z0-9]{1,})+\"", "i");
 char[][] buf = r.match(src_buf);
 while(1)
 {
 Attributes ~= new Attribute(r.exec(src_buf)[0], this);
 }

I haven't used the regexp module but glancing at the doc r.exec(src_buf) 
should return an array of matches and then you are indexing only the first 
element [0] so that is just using the first match. The doc for exec says 
"returns the next match" but then it says the return is the set of matches 
so I don't understand what it is actually doing. 

"Ben Hinkle" <ben.hinkle gmail.com> writes:

"Alexander Panek" <alexander.panek brainsware.org> wrote in message 
news:opsopz4btty2yy8c chello080109082145.3.15.vie.surfer.at...
 Hello,

 I got a little problem with the std.regexp.RegExp.match() and .exec() 
 methods. Both are just returning the first match of the pattern in the 
 string..am i doing something wrong?

 std.regexp.RegExp r = std.regexp.search(Source, 
 "([a-zA-Z]{1,})+=\"+([a-zA-Z0-9]{1,})+\"", "i");
 char[][] buf = r.match(src_buf);
 while(1)
 {
 Attributes ~= new Attribute(r.exec(src_buf)[0], this);
 }

 hoping for help =\

I think the doc for regexp is misleading and/or incomplete. I'll add some 
comments to the wiki about that page. The exec(char[]) function does not 
return the "next" match. That is what exec() does. The exec() function is 
not in the online doc but it is a public method of the RegExp class so I 
assume it is ok to call it. Here is a modified version of your posted 
example that probably comes closer to what you are looking for:

import std.regexp;
int main() {
  char[] Source = "item=\"test\", itemb=\"blah\"";
  printf("%.*s\n",Source);
  RegExp r = new RegExp("([a-zA-Z]{1,})+=\"+([a-zA-Z0-9]{1,})+\"", "i");
  char[][] t = r.exec(Source);
  printf("%d %.*s %.*s %.*s\n",t.length,t[0],t[1],t[2]);
  t = r.exec();
  printf("%d %.*s %.*s %.*s\n",t.length,t[0],t[1],t[2]);
  return 0;
}

"Alexander Panek" <alexander.panek brainsware.org> writes:

On Mon, 4 Apr 2005 19:08:45 -0400, Ben Hinkle <ben.hinkle gmail.com> wrote:

 "Alexander Panek" <alexander.panek brainsware.org> wrote in message
 news:opsopz4btty2yy8c chello080109082145.3.15.vie.surfer.at...
 Hello,

 I got a little problem with the std.regexp.RegExp.match() and .exec()
 methods. Both are just returning the first match of the pattern in the
 string..am i doing something wrong?

 std.regexp.RegExp r = std.regexp.search(Source,
 "([a-zA-Z]{1,})+=\"+([a-zA-Z0-9]{1,})+\"", "i");
 char[][] buf = r.match(src_buf);
 while(1)
 {
 Attributes ~= new Attribute(r.exec(src_buf)[0], this);
 }

 hoping for help =\

 I think the doc for regexp is misleading and/or incomplete. I'll add some
 comments to the wiki about that page. The exec(char[]) function does not
 return the "next" match. That is what exec() does. The exec() function is
 not in the online doc but it is a public method of the RegExp class so I
 assume it is ok to call it. Here is a modified version of your posted
 example that probably comes closer to what you are looking for:

 import std.regexp;
 int main() {
   char[] Source = "item=\"test\", itemb=\"blah\"";
   printf("%.*s\n",Source);
   RegExp r = new RegExp("([a-zA-Z]{1,})+=\"+([a-zA-Z0-9]{1,})+\"", "i");
   char[][] t = r.exec(Source);
   printf("%d %.*s %.*s %.*s\n",t.length,t[0],t[1],t[2]);
   t = r.exec();
   printf("%d %.*s %.*s %.*s\n",t.length,t[0],t[1],t[2]);
   return 0;
 }

You saved my day, thanks :).

Regards,
Alex

-- 
huh? did you say something? :o