• simendsjo (12/12) Mar 16 2013 Why is the function called in the template at the line of
• simendsjo (4/16) Mar 16 2013 Seems pragma(msg, fn) also has the same behavior.
• Andrej Mitrovic (2/6) Mar 16 2013 Use __traits(identifier, fn).

"simendsjo" <simendsjo gmail.com> writes:

Why is the function called in the template at the line of 
.stringof?

template t(alias fn) {
     static if(fn.stringof) // f(int i) isn't callable using ()
         enum t = true;
     else
         enum t = false;
}

void main() {
     void f(int i) {}
     t!f;
}

"simendsjo" <simendsjo gmail.com> writes:

On Saturday, 16 March 2013 at 13:01:44 UTC, simendsjo wrote:
 Why is the function called in the template at the line of 
 .stringof?

 template t(alias fn) {
     static if(fn.stringof) // f(int i) isn't callable using ()
         enum t = true;
     else
         enum t = false;
 }

 void main() {
     void f(int i) {}
     t!f;
 }

Seems pragma(msg, fn) also has the same behavior.
Guess this is because all functions can be called using property 
syntax. It really hurts my generic code though..

Andrej Mitrovic <andrej.mitrovich gmail.com> writes:

On 3/16/13, simendsjo <simendsjo gmail.com> wrote:
 Why is the function called in the template at the line of
 .stringof?

 template t(alias fn) {
      static if(fn.stringof) // f(int i) isn't callable using ()

Use __traits(identifier, fn).