• d-bugmail puremagic.com Dec 26 2009
• d-bugmail puremagic.com Jan 14 2010
• d-bugmail puremagic.com Jan 28 2010
• d-bugmail puremagic.com Jan 28 2010
• d-bugmail puremagic.com Jan 28 2010
• d-bugmail puremagic.com Jan 28 2010
• d-bugmail puremagic.com May 31 2010

d-bugmail puremagic.com writes:

http://d.puremagic.com/issues/show_bug.cgi?id=3651

           Summary: mangleof broken for enums
           Product: D
           Version: 1.051
          Platform: Other
        OS/Version: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD
        AssignedTo: nobody puremagic.com
        ReportedBy: nfxjfg gmail.com


--- Comment #0 from nfxjfg gmail.com 2009-12-26 11:32:07 PST ---
First off, this bug report is for dmd 1.053, not 1.051; but bugzilla let's me
only select up to 1.051.

.mangleof is broken for enums:

enum foo {
    item,
}

//should output a mangled name with "foo" in it, but outputs "i"
pragma(msg, foo.mangleof);

void main() {}

I apologize if this is a duplicate bug; there were quite a lot of enum bugs
which look slightly similar (the compiler seems to reduce enums to ints
prematurely in a lot of cases).

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--- Comment #1 from mpiepk gmail.com 2010-01-14 05:43:12 PST ---
Created an attachment (id=549)
Patch

Patch against dmd 1.055.
The problem is that mangleof is executed on the enum member type, not the enum
type itself.

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d-bugmail puremagic.com writes:

http://d.puremagic.com/issues/show_bug.cgi?id=3651


Don <clugdbug yahoo.com.au> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |clugdbug yahoo.com.au


--- Comment #2 from Don <clugdbug yahoo.com.au> 2010-01-28 00:47:21 PST ---
 enum foo {
     item,
 }


 //should output a mangled name with "foo" in it, but outputs "i"
 pragma(msg, foo.mangleof);


Are you sure that's what it should do? Why do you think the existing behaviour
is wrong?

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--- Comment #3 from nfxjfg gmail.com 2010-01-28 00:55:57 PST ---
 Don: I'm pretty sure my bug report is correct. enums are the *only* type that
behave different here. Further, if you get the mangle of a function or template
that use enums as parameters, the enum gets mangled using the type name, not
the base type.

Why do you think the current behavior would be correct? Why would .mangleof for
a type return the mangle for a completely *different* type?

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--- Comment #4 from Don <clugdbug yahoo.com.au> 2010-01-28 01:05:28 PST ---
(In reply to comment #3)
  Don: I'm pretty sure my bug report is correct. enums are the *only* type that
 behave different here. Further, if you get the mangle of a function or template
 that use enums as parameters, the enum gets mangled using the type name, not
 the base type.
 
 Why do you think the current behavior would be correct? Why would .mangleof for
 a type return the mangle for a completely *different* type?


Because enums aren't strong types. typeof(item) is int, not foo. 'foo' just
seems to be an alias for int. (I think the existing behaviour is stupid, BTW).

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--- Comment #5 from nfxjfg gmail.com 2010-01-28 01:14:41 PST ---
typeof(item) is int, not foo.


Even then, typeof(foo) is foo, and not int. It's only logical that foo.mangleof
should be the mangle for foo, not int.

I don't know about item.mangelof. Is that even allowed?

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Walter Bright <bugzilla digitalmars.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|NEW                         |RESOLVED
                 CC|                            |bugzilla digitalmars.com
         Resolution|                            |FIXED


--- Comment #6 from Walter Bright <bugzilla digitalmars.com> 2010-05-31
01:02:27 PDT ---
http://www.dsource.org/projects/dmd/changeset/508

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