• Sean Kelly <sean f4.ca> Jul 19 2004
• "Kris" <someidiot earthlink.dot.dot.dot.net> Jul 19 2004
• Sean Kelly <sean f4.ca> Jul 19 2004
• "Kris" <someidiot earthlink.dot.dot.dot.net> Jul 19 2004
• "Walter" <newshound digitalmars.com> Aug 15 2004

Sean Kelly <sean f4.ca> writes:

In 0.95, this fails to compile with the error "test.d(15): non-constant
expression new E"

int main()
{
class E : Exception { this() { super( "" ); } }
static E e = new E();
return 0;
}

I had been using this technique so I only had to construct internal exceptions
once.  Is there a new method I can use to do the same thing, or is this a bug?


Sean

"Kris" <someidiot earthlink.dot.dot.dot.net> writes:

I'd be willing to bet that it'd work if you split the declaration from the
assignment:

static E e;
e = new E;

Sucks? Yes ...


"Sean Kelly" <sean f4.ca> wrote in message
news:cdh1j6$jto$1 digitaldaemon.com...
 In 0.95, this fails to compile with the error "test.d(15): non-constant
 expression new E"

 int main()
 {
 class E : Exception { this() { super( "" ); } }
 static E e = new E();
 return 0;
 }

 I had been using this technique so I only had to construct internal


 once.  Is there a new method I can use to do the same thing, or is this a


 Sean

Sean Kelly <sean f4.ca> writes:

In article <cdh2hh$ker$1 digitaldaemon.com>, Kris says...
I'd be willing to bet that it'd work if you split the declaration from the
assignment:

static E e;
e = new E;

Sucks? Yes ...


You're right, that works.  How incredibly odd.  But this new syntax makes it
look like e will be initialized every time the function is called, which is not
what I want.  And I'd prefer not to have to put in a bunch of:

if( !e ) e = new E();

calls... perhaps this will be fixed in 0.96?


Sean

"Kris" <someidiot earthlink.dot.dot.dot.net> writes:

I do this kind of thing in a static constructor; but the language/compiler
would ideally support a one-time assignment to something like a "static
final", or whatever Walter would prefer to call it.

- Kris

"Sean Kelly" <sean f4.ca> wrote in message
news:cdh3hl$kou$1 digitaldaemon.com...
 In article <cdh2hh$ker$1 digitaldaemon.com>, Kris says...
I'd be willing to bet that it'd work if you split the declaration from




assignment:

static E e;
e = new E;

Sucks? Yes ...


 You're right, that works.  How incredibly odd.  But this new syntax makes


 look like e will be initialized every time the function is called, which


 what I want.  And I'd prefer not to have to put in a bunch of:

 if( !e ) e = new E();

 calls... perhaps this will be fixed in 0.96?


 Sean

"Walter" <newshound digitalmars.com> writes:

"Sean Kelly" <sean f4.ca> wrote in message
news:cdh1j6$jto$1 digitaldaemon.com...
 In 0.95, this fails to compile with the error "test.d(15): non-constant
 expression new E"

 int main()
 {
 class E : Exception { this() { super( "" ); } }
 static E e = new E();
 return 0;
 }

 I had been using this technique so I only had to construct internal


 once.  Is there a new method I can use to do the same thing, or is this a



D doesn't do the C++ thing of wrapping dynamic initializers for local
statics in a conditional. You'll need to do it manually, as in:

    static E e;
    if (!e) e = new E();