• DYH <DYH_member pathlink.com> Jul 20 2006
• Oskar Linde <oskar.lindeREM OVEgmail.com> Jul 20 2006
• "Derek Parnell" <derek psych.ward> Jul 20 2006
• DYH <DYH_member pathlink.com> Jul 20 2006

DYH <DYH_member pathlink.com> writes:

Consider this small sample:

 import std.stdio;
 
 int main(char[][] args)
 {
 	writefln(stderr, "test");
 	return 0;
 }


will output something like:
 4164D0test




Is that correct behaviour?

DMD 0.163

Oskar Linde <oskar.lindeREM OVEgmail.com> writes:

DYH wrote:
 Consider this small sample:
 
 import std.stdio;

 int main(char[][] args)
 {
 	writefln(stderr, "test");
 	return 0;
 }


 will output something like:
 4164D0test




 Is that correct behaviour?


Yes.

writef(ln) prints all of it's arguments to stdout. stdout is a 
std.c.stdio._iobuf*, i.e. a pointer. What you see is the pointer value 
being printed.

Try fwritef(ln) instead.

/Oskar

"Derek Parnell" <derek psych.ward> writes:

On Thu, 20 Jul 2006 23:30:26 +1000, DYH <DYH_member pathlink.com> wrote:

 Consider this small sample:

 import std.stdio;

 int main(char[][] args)
 {
 	writefln(stderr, "test");
 	return 0;
 }


 will output something like:
 4164D0test




 Is that correct behaviour?


Yes.

If you want to write to stderr, use this instead...

   import std.cstream;
   derr.writefln("test");


-- 
Derek Parnell
Melbourne, Australia

DYH <DYH_member pathlink.com> writes:

In article <e9o0hi$2inh$1 digitaldaemon.com>, DYH says...
Consider this small sample:

 import std.stdio;
 
 int main(char[][] args)
 {
 	writefln(stderr, "test");
 	return 0;
 }


will output something like:
 4164D0test




Is that correct behaviour?

DMD 0.163


Ok guys, thanks for your replays =)