• Roel Mathys <roel.mathys yucom.be> May 24 2004
• "Ivan Senji" <ivan.senji public.srce.hr> May 24 2004
• Roel Mathys <roel.mathys yucom.be> May 24 2004
• "Walter" <newshound digitalmars.com> May 25 2004

Roel Mathys <roel.mathys yucom.be> writes:

The first example does not compile any more on DMD090, I guess a 
side-effect of changing the casting rules.

(To the bottom of the page: http://www.digitalmars.com/d/index.html )


































































	int function(char c) fp;	// declare pointer to a function

	void test()
	{
	    static int foo(char c) { return 6; }

	    fp = foo;
	}
	

is exactly equivalent to:

	int function(char c) fp;

	void test()
	{
	    fp = function int(char c) { return 6;} ;
	}
<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<

regards,
roel

"Ivan Senji" <ivan.senji public.srce.hr> writes:

"Roel Mathys" <roel.mathys yucom.be> wrote in message
news:c8thde$96g$1 digitaldaemon.com...
 The first example does not compile any more on DMD090, I guess a
 side-effect of changing the casting rules.

 (To the bottom of the page: http://www.digitalmars.com/d/index.html )

  >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
 For example:

 int function(char c) fp; // declare pointer to a function

 void test()
 {
     static int foo(char c) { return 6; }

     fp = foo;


this should be:
fp = &foo;

 }


 is exactly equivalent to:

 int function(char c) fp;

 void test()
 {
     fp = function int(char c) { return 6;} ;
 }
 <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<

 regards,
 roel

Roel Mathys <roel.mathys yucom.be> writes:

Ivan Senji wrote:
 "Roel Mathys" <roel.mathys yucom.be> wrote in message
 news:c8thde$96g$1 digitaldaemon.com...
 
The first example does not compile any more on DMD090, I guess a
side-effect of changing the casting rules.

(To the bottom of the page: http://www.digitalmars.com/d/index.html )


































































int function(char c) fp; // declare pointer to a function

void test()
{
    static int foo(char c) { return 6; }

    fp = foo;


 
 this should be:
 fp = &foo;
 
 
}


is exactly equivalent to:

int function(char c) fp;

void test()
{
    fp = function int(char c) { return 6;} ;
}
<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<

regards,
roel


 
 


should be updated.

http://www.digitalmars.com/d/expression.html

roel

"Walter" <newshound digitalmars.com> writes:

"Roel Mathys" <roel.mathys yucom.be> wrote in message
news:c8uk0h$2ddl$1 digitaldaemon.com...
 right, but the documentation on this page concerning Function Literals
 should be updated.

 http://www.digitalmars.com/d/expression.html


Done. Thanks