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digitalmars.D - TDPL, shared data, and Phobos

reply Brian Palmer <d brian.codekitchen.net> writes:
This is really like 3 messages, but I didn't want to spam the list with topics,
and maybe I'm the only one feeling this pain anyway. So first: from the
perspective of a guy who has dabbled in D1 and D2 for years, but hasn't looked
closed at the language in ~10 months, I loved TDPL. It convinced me that D2 is
going to kick ass. Sadly though, I felt like I finished chapter 13 without
gaining any real understanding of how `shared` works in D, and how I can
effectively share mutable data when it *is* necessary. Maybe this was
intentional, and shared is just too much of an experimental feature still to
write a chapter on. But I decided to play around with some prototypes.

First, it took me ages to find any sign of any locking primitives beyond the
implied Mutex in Object. Finally I resorted to doing a `grep -ri semaphore
/usr/local/dmd2` (on OS X), and found a whole wealth of code. There's an entire
core.sync.* package! My end goal was to find or create a read/write lock, and
lo and behold, there's one all ready and containing unit tests in
core/sync/rwmutex.d.

Which leads to my first questions: why are the core.* interfaces apparently not
documented along with the std.* packages on the D web site? Is there a
documentation resource elsewhere? Even if the DDOC is sparse, at least showing
which classes exist under core.* would be a huge help. And are these
implementations ready for use by my code, or are they hidden away for a reason?

Also, is there any documentation on the actual semantics of shared?
http://www.digitalmars.com/d/2.0/attribute.html is a blank on the subject, and
the "migrating to shared" article only talks about simple global state. What
are the actual semantics of shared classes, and how do they interact with other
code? For instance, after much banging of my head against the desk, I finally
wrote a working implementation of a simple shared multi-reader var. Obviously
there are better ways to do a simple shared incrementing counter, this is just
a first experiment working toward a shared mutable 512MB trie data structure
that we have in our app's current C++ implementation:

 shared class MyValue {
     this() {
         _lock = cast(shared)new ReadWriteMutex;
     }
 
     int inc() {
         synchronized((cast(ReadWriteMutex)_lock).writer) {
             return _value++;
         }
     }
 
     int get() {
         synchronized((cast(ReadWriteMutex)_lock).reader) {
             return _value;
         }
     }
 
     private ReadWriteMutex _lock;
     private int _value;
 }
 
 shared MyValue sharedVal;
 ... seems to behave correctly with multiple threads reading and writing ...
So I can maybe understand the cast(shared) in the ctor. But I have to admit I have absolutely no idea why I had to cast away the shared attribute in the inc/get methods. Is there any documentation on what's really going on in the compiler here? It's a shared method, accessing a shared instance var, why the cast? Is the compiler upset about something in the definition of ReadWriteMutex itself? Also, how would one implement this as a struct? My postblit op generates compiler errors about casting between shared/unshared MyValue:
 shared struct MyValue {
    this(this) { _lock = cast(shared) new ReadWriteMutex; } // ERROR
    ... same as above ...
 }
I recognize the possible race conditions here, but there has to be *some* way to implement a postblit op on a shared struct? I hope this doesn't come across as empty complaining, I'm happy to help improve the documentation if I can.
Jul 13 2010
next sibling parent reply Bane <branimir.milosavljevic gmail.com> writes:
I am few days old in playin with D2 and whole shared stuff, so I am probably
wrong in something. 

You should probably declare your example class MyValue synchronized instead of
shared. It implies that class is shared too, and this way all methods are
synchronized. In D1 you could mix synchronized and non syncrhonized methods in
class, in D2 its whole or nothing. This way you don't need _lock var in your
example.

So this would work (i guess)

synchronized class MyValue {
     int inc() {
            return _value++;
      }
     int get() {
            return _value;
     }
     private int _value;
}

shared MyValue sharedVal;

void main(){
  sharedVal = new shared(MyValue );
}

 I noticed that in D1 synchronized methods of same class share same lock, while
in this D2 example (when the whole class is declared synchronized), each method
has its own lock. 

 Also, is there any documentation on the actual semantics of shared?
http://www.digitalmars.com/d/2.0/attribute.html is a blank on the subject, and
the "migrating to shared" article only talks about simple global state. What
are the actual semantics of shared classes, and how do they interact with other
code? For instance, after much banging of my head against the desk, I finally
wrote a working implementation of a simple shared multi-reader var. Obviously
there are better ways to do a simple shared incrementing counter, this is just
a first experiment working toward a shared mutable 512MB trie data structure
that we have in our app's current C++ implementation:
 
 shared class MyValue {
     this() {
         _lock = cast(shared)new ReadWriteMutex;
     }
 
     int inc() {
         synchronized((cast(ReadWriteMutex)_lock).writer) {
             return _value++;
         }
     }
 
     int get() {
         synchronized((cast(ReadWriteMutex)_lock).reader) {
             return _value;
         }
     }
 
     private ReadWriteMutex _lock;
     private int _value;
 }
 
 shared MyValue sharedVal;
 ... seems to behave correctly with multiple threads reading and writing ...
So I can maybe understand the cast(shared) in the ctor. But I have to admit I have absolutely no idea why I had to cast away the shared attribute in the inc/get methods. Is there any documentation on what's really going on in the compiler here? It's a shared method, accessing a shared instance var, why the cast? Is the compiler upset about something in the definition of ReadWriteMutex itself? Also, how would one implement this as a struct? My postblit op generates compiler errors about casting between shared/unshared MyValue:
 shared struct MyValue {
    this(this) { _lock = cast(shared) new ReadWriteMutex; } // ERROR
    ... same as above ...
 }
I recognize the possible race conditions here, but there has to be *some* way to implement a postblit op on a shared struct? I hope this doesn't come across as empty complaining, I'm happy to help improve the documentation if I can.
Jul 13 2010
parent reply Brian Palmer <d brian.codekitchen.net> writes:
It probably wasn't very clear from my simplified example, but I'm looking to
create a shared-reader-one-writer scenario. If I declare MyValue synchronized,
only one thread can be inside the get() method at a time, which defeats the
shared-reader requirement. Imagine this is a much larger more complex data
structure, where get() requires walking through multiple levels of a tree and a
binary search at the last level.

-- Brian


Bane Wrote:

 I am few days old in playin with D2 and whole shared stuff, so I am probably
wrong in something. 
 
 You should probably declare your example class MyValue synchronized instead of
shared. It implies that class is shared too, and this way all methods are
synchronized. In D1 you could mix synchronized and non syncrhonized methods in
class, in D2 its whole or nothing. This way you don't need _lock var in your
example.
 
 So this would work (i guess)
 
 synchronized class MyValue {
      int inc() {
             return _value++;
       }
      int get() {
             return _value;
      }
      private int _value;
 }
 
 shared MyValue sharedVal;
 
 void main(){
   sharedVal = new shared(MyValue );
 }
 
  I noticed that in D1 synchronized methods of same class share same lock,
while in this D2 example (when the whole class is declared synchronized), each
method has its own lock. 
 
 Also, is there any documentation on the actual semantics of shared?
http://www.digitalmars.com/d/2.0/attribute.html is a blank on the subject, and
the "migrating to shared" article only talks about simple global state. What
are the actual semantics of shared classes, and how do they interact with other
code? For instance, after much banging of my head against the desk, I finally
wrote a working implementation of a simple shared multi-reader var. Obviously
there are better ways to do a simple shared incrementing counter, this is just
a first experiment working toward a shared mutable 512MB trie data structure
that we have in our app's current C++ implementation:
 
 shared class MyValue {
     this() {
         _lock = cast(shared)new ReadWriteMutex;
     }
 
     int inc() {
         synchronized((cast(ReadWriteMutex)_lock).writer) {
             return _value++;
         }
     }
 
     int get() {
         synchronized((cast(ReadWriteMutex)_lock).reader) {
             return _value;
         }
     }
 
     private ReadWriteMutex _lock;
     private int _value;
 }
 
 shared MyValue sharedVal;
 ... seems to behave correctly with multiple threads reading and writing ...
So I can maybe understand the cast(shared) in the ctor. But I have to admit I have absolutely no idea why I had to cast away the shared attribute in the inc/get methods. Is there any documentation on what's really going on in the compiler here? It's a shared method, accessing a shared instance var, why the cast? Is the compiler upset about something in the definition of ReadWriteMutex itself? Also, how would one implement this as a struct? My postblit op generates compiler errors about casting between shared/unshared MyValue:
 shared struct MyValue {
    this(this) { _lock = cast(shared) new ReadWriteMutex; } // ERROR
    ... same as above ...
 }
I recognize the possible race conditions here, but there has to be *some* way to implement a postblit op on a shared struct? I hope this doesn't come across as empty complaining, I'm happy to help improve the documentation if I can.
Jul 17 2010
parent reply Bane <branimir.milosavljevic gmail.com> writes:
 It probably wasn't very clear from my simplified example, but I'm looking to
create a shared-reader-one-writer scenario. If I declare MyValue synchronized,
only one thread can be inside the get() method at a time, which defeats the
shared-reader requirement. Imagine this is a much larger more complex data
structure, where get() requires walking through multiple levels of a tree and a
binary search at the last level.
 
Yup, I get it. But there is one point in it: write is not atomic operation in sense that get() might return half written data, right?
Jul 17 2010
parent reply Brian Palmer <d brian.codekitchen.net> writes:
 It probably wasn't very clear from my simplified example, but I'm looking to
create a shared-reader-one-writer scenario. If I declare MyValue synchronized,
only one thread can be inside the get() method at a time, which defeats the
shared-reader requirement. Imagine this is a much larger more complex data
structure, where get() requires walking through multiple levels of a tree and a
binary search at the last level.
 
Yup, I get it. But there is one point in it: write is not atomic operation in sense that get() might return half written data, right?
No, that's why I want a read-write lock. Multiple threads can read the data, but writes take an exclusive lock. http://en.wikipedia.org/wiki/Readers-writer_lock
Jul 20 2010
parent reply "Robert Jacques" <sandford jhu.edu> writes:
On Tue, 20 Jul 2010 15:41:31 -0400, Brian Palmer <d brian.codekitchen.net>  
wrote:

 It probably wasn't very clear from my simplified example, but I'm  
looking to create a shared-reader-one-writer scenario. If I declare MyValue synchronized, only one thread can be inside the get() method at a time, which defeats the shared-reader requirement. Imagine this is a much larger more complex data structure, where get() requires walking through multiple levels of a tree and a binary search at the last level.

 Yup, I get it. But there is one point in it: write is not atomic  
 operation in sense that get() might return half written data, right?
No, that's why I want a read-write lock. Multiple threads can read the data, but writes take an exclusive lock. http://en.wikipedia.org/wiki/Readers-writer_lock
Have you tried core.sync.rwmutex? Also, please remember that CREW locks are not composable and can easily lead to dead-locks.
Jul 21 2010
next sibling parent Brian Palmer <d brian.codekitchen.net> writes:
Robert Jacques Wrote:

 On Tue, 20 Jul 2010 15:41:31 -0400, Brian Palmer <d brian.codekitchen.net>  
 wrote:
 
 It probably wasn't very clear from my simplified example, but I'm  
looking to create a shared-reader-one-writer scenario. If I declare MyValue synchronized, only one thread can be inside the get() method at a time, which defeats the shared-reader requirement. Imagine this is a much larger more complex data structure, where get() requires walking through multiple levels of a tree and a binary search at the last level.

 Yup, I get it. But there is one point in it: write is not atomic  
 operation in sense that get() might return half written data, right?
No, that's why I want a read-write lock. Multiple threads can read the data, but writes take an exclusive lock. http://en.wikipedia.org/wiki/Readers-writer_lock
Have you tried core.sync.rwmutex? Also, please remember that CREW locks are not composable and can easily lead to dead-locks.
lol, yes, that's how this thread started was with a discussion of core.sync.rwmutex.
Jul 22 2010
prev sibling parent reply awishformore <awishformore nospam.plz> writes:
On 22/07/2010 01:49, Robert Jacques wrote:
 On Tue, 20 Jul 2010 15:41:31 -0400, Brian Palmer
 <d brian.codekitchen.net> wrote:

 It probably wasn't very clear from my simplified example, but I'm
looking to create a shared-reader-one-writer scenario. If I declare MyValue synchronized, only one thread can be inside the get() method at a time, which defeats the shared-reader requirement. Imagine this is a much larger more complex data structure, where get() requires walking through multiple levels of a tree and a binary search at the last level.

 Yup, I get it. But there is one point in it: write is not atomic
 operation in sense that get() might return half written data, right?
No, that's why I want a read-write lock. Multiple threads can read the data, but writes take an exclusive lock. http://en.wikipedia.org/wiki/Readers-writer_lock
Have you tried core.sync.rwmutex? Also, please remember that CREW locks are not composable and can easily lead to dead-locks.
Afaik, the current rwmutex is a wrapper around two separate mutexes (one for readers, one for writers) and you have to decide whether readers or writers get precedence, meaning that ether all writers in the queue have to wait if just one reader has to write or all writers in the queue have to wait if there is a single reader comes up. This is very unlike the behaviour I would like to see; I would expect readers and writers to be in the same queue, meaning the only difference between the rw and the normal mutex would be that all subsequent readers in the queue can read at the same time. /Max
Jul 22 2010
parent reply Sean Kelly <sean invisibleduck.org> writes:
awishformore Wrote:

 On 22/07/2010 01:49, Robert Jacques wrote:
 Have you tried core.sync.rwmutex? Also, please remember that CREW locks
 are not composable and can easily lead to dead-locks.
Afaik, the current rwmutex is a wrapper around two separate mutexes (one for readers, one for writers) and you have to decide whether readers or writers get precedence, meaning that ether all writers in the queue have to wait if just one reader has to write or all writers in the queue have to wait if there is a single reader comes up. This is very unlike the behaviour I would like to see; I would expect readers and writers to be in the same queue, meaning the only difference between the rw and the normal mutex would be that all subsequent readers in the queue can read at the same time.
ReadWriteMutex exposes a read and write interface, but there certainly aren't two actual mutexes underneath. It's true that the implementation doesn't explicitly maintain a queue, but this is intentional. If readers and writers in the queue have different thread priorities set, those priorities should be honored, and it's pointless to write all that code in druntime when the OS takes care of it for us. Instead, those waiting for access to the mutex all block on a condition variable and whoever wakes up first wins. It's up the OS to make sure that thread priorities are honored and starvation doesn't occur.
Jul 22 2010
parent reply Graham St Jack <Graham.StJack internode.on.net> writes:
On 23/07/10 10:23, Sean Kelly wrote:
 awishformore Wrote:

    
 On 22/07/2010 01:49, Robert Jacques wrote:
      
 Have you tried core.sync.rwmutex? Also, please remember that CREW locks
 are not composable and can easily lead to dead-locks.
        
Afaik, the current rwmutex is a wrapper around two separate mutexes (one for readers, one for writers) and you have to decide whether readers or writers get precedence, meaning that ether all writers in the queue have to wait if just one reader has to write or all writers in the queue have to wait if there is a single reader comes up. This is very unlike the behaviour I would like to see; I would expect readers and writers to be in the same queue, meaning the only difference between the rw and the normal mutex would be that all subsequent readers in the queue can read at the same time.
ReadWriteMutex exposes a read and write interface, but there certainly aren't two actual mutexes underneath. It's true that the implementation doesn't explicitly maintain a queue, but this is intentional. If readers and writers in the queue have different thread priorities set, those priorities should be honored, and it's pointless to write all that code in druntime when the OS takes care of it for us. Instead, those waiting for access to the mutex all block on a condition variable and whoever wakes up first wins. It's up the OS to make sure that thread priorities are honored and starvation doesn't occur.
It isn't clear that thread priorities will do the job here. I have been burned before by things like priority inheritance chaining, and other ways that thread priorities can be elevated for potentially long periods of time. Priority inheritance chaining goes like this: Thread low locks mutex A, then mutex B Thread high tries to lock mutex B, elevating low's priority to high's so that high can get the mutex quickly. When thread low releases mutex B (letting high get it), the OS has trouble figuring out what low's priority should now be, and leaves it elevated until it releases all mutexes it still has (mutex A in this case). Low is now running at a high priority, preventing thread medium from getting any CPU. This scenario happened for me with vxWorks some time back, and is the reason I no longer do much work at all while I have a mutex locked. I am confident that it is a real problem to this day. -- Graham St Jack
Jul 22 2010
parent =?UTF-8?B?IkrDqXLDtG1lIE0uIEJlcmdlciI=?= <jeberger free.fr> writes:
Graham St Jack wrote:
 Priority inheritance chaining goes like this:
=20
 Thread low locks mutex A, then mutex B
=20
 Thread high tries to lock mutex B, elevating low's priority to high's s=
o
 that high can get the mutex quickly.
=20
 When thread low releases mutex B (letting high get it), the OS has
 trouble figuring out what low's priority should now be, and leaves it
 elevated until it releases all mutexes it still has (mutex A in this ca=
se).
=20
 Low is now running at a high priority, preventing thread medium from
 getting any CPU.
=20
=20
 This scenario happened for me with vxWorks some time back, and is the
 reason I no longer do much work at all while I have a mutex locked. I a=
m
 confident that it is a real problem to this day.
=20
This is only a problem on real-time OSes where high priority threads prevent low priority ones from running at all. On non real-time OSes like Windows, Linux, *BSD and MacOS, low priority threads will always get some CPU cycles too, and AFAIK thread priorities are never elevated in the way you describe. That being said, it is always a good practice to spend as little time as possible holding a lock (whether a mutex or a file lock or whatever). Jerome --=20 mailto:jeberger free.fr http://jeberger.free.fr Jabber: jeberger jabber.fr
Jul 23 2010
prev sibling parent reply Sean Kelly <sean invisibleduck.org> writes:
The casts are necessary because I haven't yet applied 'shared' to druntime.  I
ran into a few issues when doing so and rolled back my changes.  I'll give it
another shot before the next release.
Jul 17 2010
next sibling parent reply Graham St Jack <graham.stjack internode.on.net> writes:
On Sat, 17 Jul 2010 11:42:03 -0400, Sean Kelly wrote:

 The casts are necessary because I haven't yet applied 'shared' to
 druntime.  I ran into a few issues when doing so and rolled back my
 changes.  I'll give it another shot before the next release.
I'm glad you announced you intention - I was just about to roll up my sleeves and give it a go for Condition, but will wait for the next release. Like all my previous attempts to use shared, I have waited for quite a while for things to improve, tried using shared again, hit a brick wall and resorted to defeating the compiler's detection of shared data. TDPL raised my hopes without actually making it clear how to use synchronized classes. Alas, it seems to me that they still aren't usable in practice. With any luck the problems are just library issues which can be fixed relatively easily. Like Brian Palmer, I am frustrated by the lack of documentation about shared and druntime's sync package, and am happy to lend a hand if that would be helpful. The code I am trying to write is a simple synchronized class with a Condition, but I can't create a Condition on a shared "this". A cut-down version of what I want to write is: synchronized class Foo { Condition mCondition; this() { mCondition = cast(shared) new Condition(this); } void some_method() { } } I realise that Condition wants a Mutex, but a synchronized class already has an implicit one which is implicitly used by all the methods, so the above is definitely what I want to write. What I have to write instead (which avoids the compiler noticing that anything is being shared) is: class Foo { Mutex mMutex; Condition mCondition; this() { mMutex = new Mutex(); mCondition = new Condition(mMutex); } void some_method() { synchronized(mMutex) { } } } The latter works just fine, but it is very disappointing after all the fuss about how important shared is that you can't actually use it for the most mainstream of all uses - a synchronized class with a condition (which is what a message queue between threads is supposed to be).
Jul 17 2010
next sibling parent reply Sean Kelly <sean invisibleduck.org> writes:
Graham St Jack <graham.stjack internode.on.net> wrote:
 On Sat, 17 Jul 2010 11:42:03 -0400, Sean Kelly wrote:
 
 The casts are necessary because I haven't yet applied 'shared' to
 druntime.  I ran into a few issues when doing so and rolled back my
 changes.  I'll give it another shot before the next release.
I'm glad you announced you intention - I was just about to roll up my sleeves and give it a go for Condition, but will wait for the next release. Like all my previous attempts to use shared, I have waited for quite a while for things to improve, tried using shared again, hit a brick wall and resorted to defeating the compiler's detection of shared data. TDPL raised my hopes without actually making it clear how to use synchronized classes. Alas, it seems to me that they still aren't usable in practice. With any luck the problems are just library issues which can be fixed relatively easily. Like Brian Palmer, I am frustrated by the lack of documentation about shared and druntime's sync package, and am happy to lend a hand if that would be helpful. The code I am trying to write is a simple synchronized class with a Condition, but I can't create a Condition on a shared "this". A cut-down version of what I want to write is: synchronized class Foo { Condition mCondition; this() { mCondition = cast(shared) new Condition(this); } void some_method() { } } I realise that Condition wants a Mutex, but a synchronized class already has an implicit one which is implicitly used by all the methods, so the above is definitely what I want to write. What I have to write instead (which avoids the compiler noticing that anything is being shared) is: class Foo { Mutex mMutex; Condition mCondition; this() { mMutex = new Mutex(); mCondition = new Condition(mMutex); } void some_method() { synchronized(mMutex) { } } } The latter works just fine, but it is very disappointing after all the fuss about how important shared is that you can't actually use it for the most mainstream of all uses - a synchronized class with a condition (which is what a message queue between threads is supposed to be).
new Mutex(this) makes the mutex the object monitor, so it will be what's locked for synchronized functions.
Jul 18 2010
parent Graham St Jack <graham.stjack internode.on.net> writes:
On Sun, 18 Jul 2010 16:05:08 +0000, Sean Kelly wrote:

 Graham St Jack <graham.stjack internode.on.net> wrote:
 On Sat, 17 Jul 2010 11:42:03 -0400, Sean Kelly wrote:
 
 The casts are necessary because I haven't yet applied 'shared' to
 druntime.  I ran into a few issues when doing so and rolled back my
 changes.  I'll give it another shot before the next release.
I'm glad you announced you intention - I was just about to roll up my sleeves and give it a go for Condition, but will wait for the next release. Like all my previous attempts to use shared, I have waited for quite a while for things to improve, tried using shared again, hit a brick wall and resorted to defeating the compiler's detection of shared data. TDPL raised my hopes without actually making it clear how to use synchronized classes. Alas, it seems to me that they still aren't usable in practice. With any luck the problems are just library issues which can be fixed relatively easily. Like Brian Palmer, I am frustrated by the lack of documentation about shared and druntime's sync package, and am happy to lend a hand if that would be helpful. The code I am trying to write is a simple synchronized class with a Condition, but I can't create a Condition on a shared "this". A cut-down version of what I want to write is: synchronized class Foo { Condition mCondition; this() { mCondition = cast(shared) new Condition(this); } void some_method() { } } I realise that Condition wants a Mutex, but a synchronized class already has an implicit one which is implicitly used by all the methods, so the above is definitely what I want to write. What I have to write instead (which avoids the compiler noticing that anything is being shared) is: class Foo { Mutex mMutex; Condition mCondition; this() { mMutex = new Mutex(); mCondition = new Condition(mMutex); } void some_method() { synchronized(mMutex) { } } } The latter works just fine, but it is very disappointing after all the fuss about how important shared is that you can't actually use it for the most mainstream of all uses - a synchronized class with a condition (which is what a message queue between threads is supposed to be).
new Mutex(this) makes the mutex the object monitor, so it will be what's locked for synchronized functions.
That's cool. I look forward to shared not being an issue ;-) I assume that when Condition and Mutex are shareable, I will then (from your other post) write: synchronized class Foo { Mutex mMutex; Condition mCondition; this() { mMutex = cast(shared) new Mutex(this); mCondition = cast(shared) new Condition(mMutex); } void some_method() { ... mCondition.notify; // ok because mMutex is locked } }
Jul 19 2010
prev sibling parent Sean Kelly <sean invisibleduck.org> writes:
Graham St Jack Wrote:
 
 The code I am trying to write is a simple synchronized class with a 
 Condition, but I can't create a Condition on a shared "this".
 
 A cut-down version of what I want to write is:
 
 synchronized class Foo {
   Condition mCondition;
   this() {
     mCondition = cast(shared) new Condition(this);
   }
   void some_method() {
   }
 }
 
 I realise that Condition wants a Mutex, but a synchronized class already 
 has an implicit one which is implicitly used by all the methods, so the 
 above is definitely what I want to write.
The built-in mutex is created on first use, so what you can do is drop in core.sync.mutex.Mutex before this happens (the library Mutex can be assigned as an object monitor). If 'shared' weren't an issue, the code would be: synchronized class Foo { Condition mCond; Mutex mLock; this() { mLock = new Mutex(this); // make mutex this object's monitor mCond = new Condition(mLock); // bind condition to mLock } void some_method() { // locks mLock mLock.notify(); // safe because mLock is locked } }
Jul 18 2010
prev sibling parent reply Brian Palmer <d brian.codekitchen.net> writes:
Thanks Sean, it's great to at least know where the issue is. As to my other
question, why do the D std library docs at
http://www.digitalmars.com/d/2.0/phobos/phobos.html have no indication that
core.sync and the other core.* packages even exist? Are the APIs not stable
enough yet to treat them as public? Even if documentation is sparse, just
knowing that RWLock existed and its exposed methods was all I really needed to
start using it, aside from the shared issue.

-- Brian


Sean Kelly Wrote:

 The casts are necessary because I haven't yet applied 'shared' to druntime.  I
ran into a few issues when doing so and rolled back my changes.  I'll give it
another shot before the next release.
Jul 20 2010
parent Sean Kelly <sean invisibleduck.org> writes:
The core stuff is in a different repository, and I haven't done all the
work to integrate the docs yet. I sent a file to do most of this to the
Phobos list though, if you're inclined to track it down. 

Brian Palmer <d brian.codekitchen.net> wrote:
 Thanks Sean, it's great to at least know where the issue is. As to my
 other question, why do the D std library docs at
 http://www.digitalmars.com/d/2.0/phobos/phobos.html have no indication
 that core.sync and the other core.* packages even exist? Are the APIs
 not stable enough yet to treat them as public? Even if documentation
 is sparse, just knowing that RWLock existed and its exposed methods
 was all I really needed to start using it, aside from the shared
 issue.
 
 -- Brian
 
 
 Sean Kelly Wrote:
 
 The casts are necessary because I haven't yet applied 'shared' to
 druntime.  I ran into a few issues when doing so and rolled back my
 changes.  I'll give it another shot before the next release.
Jul 22 2010