• terranium <spam here.lot> Apr 28 2008

terranium <spam here.lot> writes:

     a[] = n;
     a[] = b[];
     a[] = b[] + c[];
     a[] = f(b[]);
 
 would mean
 
     foreach(ref e;a) e = n;
     foreach(i,ref e;a) e = b[i];
     foreach(i,ref e;a) e = b[i] + c[i];
     foreach(i,ref e;a) e = f(b[i]);
 


 solved like:
 
 foo(array[]);


This is better but still is too inobvious.
How about making it a variant of foreach?

foreach a[] = n;
foreach a[] = b[];
foreach a[] = b[] + c[];
foreach a[] = f(b[]);
foreach { a[] = f(b[]); d[]=b[]+c[]; }