• Evil Mr Henry <Evil_member pathlink.com> Jun 30 2004
• "Matthew" <admin stlsoft.dot.dot.dot.dot.org> Jun 30 2004
• "Dan Williams" <dnews ithium.NOSPAM.net> Jul 01 2004
• Arcane Jill <Arcane_member pathlink.com> Jul 01 2004
• "Walter" <newshound digitalmars.com> Jul 01 2004

Evil Mr Henry <Evil_member pathlink.com> writes:

Linux, current compiler as of June 30. The following code:

import std.string;
void main() {
char* num = "x";
char[] testName = std.string.toString(num);
printf("%s\n", std.string.toStringz("1234567890123" ~ testName));
printf("%s\n", std.string.toStringz("12345678901234" ~ testName));
printf("%s\n", std.string.toStringz("123456789012345" ~ testName));
printf("%s\n", std.string.toStringz("1234567890123456" ~ testName));
printf("%s\n", std.string.toStringz("12345678901234567" ~ testName));
}

will output:
1234567890123x
12345678901234x
123456789012345xÿ
1234567890123456x
12345678901234567x

Notice the accented y? It shouldn't be there. This only occurs if the total
string is 16 characters long, and includes a char[].

"Matthew" <admin stlsoft.dot.dot.dot.dot.org> writes:

You should post this on the bugs NG

"Evil Mr Henry" <Evil_member pathlink.com> wrote in message
news:cbvumd$2b9d$1 digitaldaemon.com...
 Linux, current compiler as of June 30. The following code:

 import std.string;
 void main() {
 char* num = "x";
 char[] testName = std.string.toString(num);
 printf("%s\n", std.string.toStringz("1234567890123" ~ testName));
 printf("%s\n", std.string.toStringz("12345678901234" ~ testName));
 printf("%s\n", std.string.toStringz("123456789012345" ~ testName));
 printf("%s\n", std.string.toStringz("1234567890123456" ~ testName));
 printf("%s\n", std.string.toStringz("12345678901234567" ~ testName));
 }

 will output:
 1234567890123x
 12345678901234x
 123456789012345xÿ
 1234567890123456x
 12345678901234567x

 Notice the accented y? It shouldn't be there. This only occurs if the total
 string is 16 characters long, and includes a char[].

"Dan Williams" <dnews ithium.NOSPAM.net> writes:

I cannot reproduce this bug.

Using: DMD 0.9.4, RHEL 3.0, 2.4.21 kernel, GCC 3.2.3, can't think of
anything else important

Also tried on my WinXP system out of interest but no bug there either ;)

My output on both systems is simply:

1234567890123x
12345678901234x
123456789012345x
1234567890123456x
12345678901234567x

What Linux distro and version are you running, with what kernel, and what
version of GCC?



"Evil Mr Henry" <Evil_member pathlink.com> wrote in message
news:cbvumd$2b9d$1 digitaldaemon.com...
 Linux, current compiler as of June 30. The following code:

 import std.string;
 void main() {
 char* num = "x";
 char[] testName = std.string.toString(num);
 printf("%s\n", std.string.toStringz("1234567890123" ~ testName));
 printf("%s\n", std.string.toStringz("12345678901234" ~ testName));
 printf("%s\n", std.string.toStringz("123456789012345" ~ testName));
 printf("%s\n", std.string.toStringz("1234567890123456" ~ testName));
 printf("%s\n", std.string.toStringz("12345678901234567" ~ testName));
 }

 will output:
 1234567890123x
 12345678901234x
 123456789012345xÿ
 1234567890123456x
 12345678901234567x

 Notice the accented y? It shouldn't be there. This only occurs if the


 string is 16 characters long, and includes a char[].

Arcane Jill <Arcane_member pathlink.com> writes:

In article <cbvumd$2b9d$1 digitaldaemon.com>, Evil Mr Henry says...
Notice the accented y? It shouldn't be there. This only occurs if the total
string is 16 characters long, and includes a char[].


**** This bug is caused by a terminating uninitialized char ****

Report it in the bugs newsgroup, and tell them the above. Meanwhile, I suggest
you do what I did - go back to DMD 0.92.

Arcane Jill

"Walter" <newshound digitalmars.com> writes:

This problem was corrected in 0.94, check the date on your copy of
libphobos.a.

"Evil Mr Henry" <Evil_member pathlink.com> wrote in message
news:cbvumd$2b9d$1 digitaldaemon.com...
 Linux, current compiler as of June 30. The following code:

 import std.string;
 void main() {
 char* num = "x";
 char[] testName = std.string.toString(num);
 printf("%s\n", std.string.toStringz("1234567890123" ~ testName));
 printf("%s\n", std.string.toStringz("12345678901234" ~ testName));
 printf("%s\n", std.string.toStringz("123456789012345" ~ testName));
 printf("%s\n", std.string.toStringz("1234567890123456" ~ testName));
 printf("%s\n", std.string.toStringz("12345678901234567" ~ testName));
 }

 will output:
 1234567890123x
 12345678901234x
 123456789012345xÿ
 1234567890123456x
 12345678901234567x

 Notice the accented y? It shouldn't be there. This only occurs if the


 string is 16 characters long, and includes a char[].